Jer*_*nce 1 generics hibernate hibernate-mapping
我想用Hibernate映射超类中的泛型字段.
我的母班是:
@Entity
@Table(name = "ParameterValue")
@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
@DiscriminatorColumn(name = "parameterType", discriminatorType = DiscriminatorType.STRING)
public abstract class ParameterValue<C>
{
private C value;
/* HELP NEEDED HERE */
public C getValue()
{
return value;
}
public void setValue(C value)
{
this.value = value;
}
}
Run Code Online (Sandbox Code Playgroud)
一个子类:
@Entity
@DiscriminatorValue(value = "integer")
@AttributeOverride(name = "value", column = @Column(name = "intValue"))
public class IntegerParameterValue extends ParameterValue<Integer>
{
}
Run Code Online (Sandbox Code Playgroud)
如您所见,我重写值字段以指定在数据库中使用的列.我的表ParameterValue由几列组成,每种类型一列.
CREATE TABLE `ParameterValue` (
`intValue` int(11) DEFAULT NULL,
`doubleValue` double DEFAULT NULL,
`stringValue` text
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
Run Code Online (Sandbox Code Playgroud)
但是hibernate抱怨说:
ParameterValue.value has an unbound type and no explicit target entity. Resolve this Generic usage issue or set an explicit target attribute (eg @OneToMany(target=) or use an explicit @Type
Run Code Online (Sandbox Code Playgroud)
好的,但是超类中getValue的良好配置是什么?(我已经发表评论"需要帮助")
我很确定你不能将一个Java属性映射到三个不同的列.你将不得不使用这个:
@Entity
@Table(name = "ParameterValue")
@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
@DiscriminatorColumn(name = "parameterType", discriminatorType = DiscriminatorType.STRING)
public abstract class ParameterValue<C> {
public abstract C getValue();
public abstract void setValue(C value);
}
@Entity
@DiscriminatorValue(value = "integer")
public class IntegerParameterValue extends ParameterValue<Integer> {
@Column(name = "intValue")
private Integer intValue;
@Override
public Integer getValue() {
return intValue;
}
@Override
public void setValue(Integer value) {
this.intValue = value;
}
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
4205 次 |
| 最近记录: |