Sup*_*ing 324 python datetime epoch
我有一个Python datetime对象,我想转换为unix时间,或自1970年代以来的秒/毫秒.
我该怎么做呢?
Sop*_*ert 443
在我看来,最简单的方法是
import datetime
epoch = datetime.datetime.utcfromtimestamp(0)
def unix_time_millis(dt):
return (dt - epoch).total_seconds() * 1000.0
Run Code Online (Sandbox Code Playgroud)
esh*_*han 126
在Python 3.3中,添加新方法.
datetime.timestamp()
Run Code Online (Sandbox Code Playgroud)
https://docs.python.org/3.3/library/datetime.html#datetime.datetime.timestamp
mik*_*iku 94
>>> import datetime
>>> # replace datetime.datetime.now() with your datetime object
>>> int(datetime.datetime.now().strftime("%s")) * 1000
1312908481000
Run Code Online (Sandbox Code Playgroud)
或者时间模块的帮助(没有日期格式化):
>>> import datetime, time
>>> # replace datetime.datetime.now() with your datetime object
>>> time.mktime(datetime.datetime.now().timetuple()) * 1000
1312908681000.0
Run Code Online (Sandbox Code Playgroud)
在http://pleac.sourceforge.net/pleac_python/datesandtimes.html的帮助下回答
文档:
wor*_*ins 14
您可以使用Delorean在空间和时间旅行!
import datetime
import delorean
dt = datetime.datetime.utcnow()
delorean.Delorean(dt, timezone="UTC").epoch
Run Code Online (Sandbox Code Playgroud)
http://delorean.readthedocs.org/en/latest/quickstart.html
est*_*ani 13
我是这样做的:
from datetime import datetime
from time import mktime
dt = datetime.now()
sec_since_epoch = mktime(dt.timetuple()) + dt.microsecond/1000000.0
millis_since_epoch = sec_since_epoch * 1000
Run Code Online (Sandbox Code Playgroud)
Ank*_*wal 13
来自模块的Python 2.7文档的推荐time
from datetime import datetime
from calendar import timegm
# Note: if you pass in a naive dttm object it's assumed to already be in UTC
def unix_time(dttm=None):
if dttm is None:
dttm = datetime.utcnow()
return timegm(dttm.utctimetuple())
print "Unix time now: %d" % unix_time()
print "Unix timestamp from an existing dttm: %d" % unix_time(datetime(2014, 12, 30, 12, 0))
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
341376 次 |
| 最近记录: |