Chr*_*her 6 windows-phone-7 restsharp
我在Windows Phone 7上使用RestSharp查明如何发出GET请求时遇到了麻烦.所有示例都显示发出POST请求,但我只需要GET.我该怎么做呢?
Joh*_*han 16
GET是RestSharp使用的默认方法,因此如果您不指定方法,它将使用GET:
var client = new RestClient("http://example.com");
var request = new RestRequest("api");
client.ExecuteAsync(request, response => {
// do something with the response
});
Run Code Online (Sandbox Code Playgroud)
此代码将发出GET请求http://example.com/api
.如果您需要添加URL参数,可以执行以下操作:
var client = new RestClient("http://example.com");
var request = new RestRequest("api");
request.AddParameter("foo", "bar");
Run Code Online (Sandbox Code Playgroud)
这转化为 http://example.com/api?foo=bar
您要找的东西就在这里。
涵盖您的场景的代码片段如下(request.Method
应设置为Method.GET
):
public void GetLabelFeed(string label, Action<Model.Feed> success, Action<string> failure)
{
string resource = "reader/api/0/stream/contents/user/-/label/" + label;
var request = GetBaseRequest();
request.Resource = resource;
request.Method = Method.GET;
request.AddParameter("n", 20); //number to return
_client.ExecuteAsync<Model.Feed>(request, (response) =>
{
if (response.ResponseStatus == ResponseStatus.Error)
{
failure(response.ErrorMessage);
}
else
{
success(response.Data);
}
});
}
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
8047 次 |
最近记录: |