Dis*_*ker 3 c++ recursion vector data-structures
问题是返回给定数组中总和达到目标的任意一种组合。我是 C++ 新手。如何完成下面的函数howSum()?我不能在这里返回 null,因为返回类型是向量。另外,我在传递向量时遇到了麻烦。
JavaScript:
const howSum = (targetSum, numbers) => {
if (targetSum === 0) return [];
if (targetSum < 0) return null;
for (let num of numbers) {
const remainder = targetSum - num;
const remainderResult = howSum(remainder, numbers);
if (remainderResult !== null)
{
return [...remainderResult, num];
}
}
return null;
};
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C++:
vector<int> howSum(int targetSum, vector<int> numbers)
{
if(targetSum == 0) return {};
if(targetSum < 0) return; //can't return null here in C++
for (int i = 0; i < numbers.size(); i++)
{
int remainder = targetSum - numbers[i];
vector<int> remainderResult = howSum(remainder, numbers);
if(pass)
{
pass
}
}
}
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让您的函数返回一个布尔值来指示向量结果(作为输出参数返回)是否有效。无论如何,将数组(向量)作为输出参数引用传递可能比作为返回值更有效。(尽管现在现代编译器可以进行一些惊人的优化。)
bool howSum(int targetSum, const std::vector<int>& numbers, std::vector<int>& result)
{
result.clear();
if (targetSum == 0) {
return true;
}
if (targetSum < 0) {
return false;
}
for (int num : numbers) {
const int remainder = targetSum - num;
bool recursion_result = howSum(remainder, numbers, result);
if (recursion_result) {
result.push_back(num);
return true;
}
}
return false;
}
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您可以使用 C++17std::optional并std::nullopt在它不包含值时返回。
#include <optional>
#include <vector>
std::optional<std::vector<int>>
howSum(int targetSum, const std::vector<int>& numbers) {
if (targetSum == 0)
return std::vector<int>{};
if (targetSum < 0)
return std::nullopt;
for (auto numer : numbers) {
const auto remainder = targetSum - numer;
auto remainderResult = howSum(remainder, numbers);
if (remainderResult) {
remainderResult->push_back(targetSum);
return remainderResult;
}
}
return std::nullopt;
}
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