oru*_*dyy 4 python exception traceback python-3.8
我想知道是否有一种简单的方法可以防止Python回溯在出现错误时打印文件的完整路径。例如,下面的回溯打印生成异常的文件的绝对路径:
Traceback (most recent call last):
File "C:/Users/user/Documents/project/project_align/src/main.py", line 62, in <module>
raise Exception
Exception
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我希望它只打印相对路径:project_align/src/main.py
是否有某个配置参数可以强制执行此操作?
我不知道是否有一个标志可以执行此操作,但如果您确实愿意,您可以使用自己的函数覆盖 sys.excepthook,在其中您可以创建 TracebackException,从帧摘要中删除所有文件名,并格式化和打印它。
import os
import sys
import traceback
def handler(_exception_type, _value, t):
exc = traceback.TracebackException(_exception_type, _value, t)
# replace file names for each frame summary
for frame_summary in exc.stack:
frame_summary.filename = os.path.relpath(frame_summary.filename)
# format and print the exception
print(''.join(exc.format()), file=sys.stderr)
sys.excepthook = handler
def crashes_hard():
print(1 / 0)
def crashes():
crashes_hard()
crashes()
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输出是
Traceback (most recent call last):
File "scratch_1.py", line 31, in <module>
crashes()
File "scratch_1.py", line 28, in crashes
crashes_hard()
File "scratch_1.py", line 24, in crashes_hard
print(1 / 0)
ZeroDivisionError: division by zero
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原始输出是
Traceback (most recent call last):
File "/home/abhijat/.config/.../scratches/scratch_1.py", line 31, in <module>
crashes()
File "/home/abhijat/.config/.../scratches/scratch_1.py", line 28, in crashes
crashes_hard()
File "/home/abhijat/.config/.../scratches/scratch_1.py", line 24, in crashes_hard
print(1 / 0)
ZeroDivisionError: division by zero
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