如何解决 TypeError: element_to_be_clickable() 需要 1 个位置参数?

Mik*_*key 3 python selenium element web-scraping selenium-chromedriver

TypeError: element_to_be_clickable() takes 1 positional argument but 2 were given当我运行以下代码时出现错误:

from selenium.webdriver.chrome.service import Service
from webdriver_manager.chrome import ChromeDriverManager
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

url = 'https://www.expedia.co.uk/'

s = Service(ChromeDriverManager().install())
chrome_options = webdriver.ChromeOptions()
chrome_options.add_experimental_option("excludeSwitches", ['enable-automation'])
driver = webdriver.Chrome(service=s, options=chrome_options)

driver.get(url)
elem = WebDriverWait(driver, 10).until(EC.element_to_be_clickable(By.CSS_SELECTOR, "#add-flight-switch"))
elem.click()
elem1 = driver.find_element(By.XPATH, "button[aria-label='Leaving from']").text
driver.quit()
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我可以看到函数中确实有两个参数elements_to_be_clickable(),但是该By.CSS_SELECTOR部分不需要通过特定的选择器类型(在本例中为 CSS)来查找吗?

我正在使用选择器中心来获取 CSS_SELECTOR 信息。

非常感谢任何有关如何解决的支持。

Guy*_*Guy 6

您确实需要两个By值 和 该值,但该函数期望将两个值打包为一,在一个tuple

EC.element_to_be_clickable((By.CSS_SELECTOR, "#add-flight-switch"))
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如果深入查看源代码,您将看到内部element_to_be_clickable使用_find_element,此函数解压tuple要在中使用driver.find_element()

class element_to_be_clickable(object):
    def __init__(self, locator):
        self.locator = locator

    def __call__(self, driver):
        element = visibility_of_element_located(self.locator)(driver)
    ...

class visibility_of_element_located(object):
    def __init__(self, locator):
        self.locator = locator

    def __call__(self, driver):
        return _element_if_visible(_find_element(driver, self.locator))
    ...

def _find_element(driver, by):
    ...
    return driver.find_element(*by)
    ...
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