Deb*_*bie 5 python json jmespath
下面是一个 JSON 示例:
{
"School": [
{"@id": "ABC_1",
"SchoolType": {"@tc": "10023204",
"#text": "BLUE FOX"}},
{"@id": "ABC_2",
"SchoolType": {"@tc": "143", "#text": "AN EAGLE"}},
{"@id": "ABC_3",
"SchoolType": {"@tc": "21474836", "#text": "OTHER REASONS"},
"SchoolStatus": {"@tc": "21474836", "#text": "FINE"},
"Teacher": [
{"@id": "XYZ_1",
"TeacherType": {"@tc": "5", "#text": "GENDER"},
"Gender": "FEMALE",
"Extension": {"@VC": "23",
"Extension_Teacher": {"DateDuration": {"@tc": "10023111",
"#text": "0-6 MONTHS"}}}},
{"@id": "XYZ_2",
"TeacherType": {"@tc": "23", "#text": "EDUCATED"},
"Extension": {"@VC": "23",
"Extension_Teacher": {"DateDuration": {"@tc": "10023111",
"#text": "CURRENT"}}}}]},
{"@id": "ABC_4",
"SchoolType": {"@tc": "21474836", "#text": "OTHER DAYS"},
"SchoolStatus": {"@tc": "1", "#text": "DOING OKAY"},
"Extension": {"Extension_School": {"AdditionalDetails": "CHRISTMAS DAY"}}}]
}
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我想提取每个关联包含“OTHER”的Teacher信息(TeacherType等Gender)。Teacher @idSchoolType.\"#text\"School @idSchool
我尝试了以下查询,但它不起作用:
School[?SchoolType.\"#text\".contains(@, "OTHER")].Teacher[*].TeacherType.\"#text\"[]]
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您必须以contains这种方式围绕条件数组扭曲函数:
[?contains(SchoolType."#text", 'OTHER')]
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因此,获取完整对象的方法Teacher是:
School[?contains(SchoolType."#text", 'OTHER')].Teacher
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或者,使用展平运算符摆脱数组的数组:
School[?contains(SchoolType."#text", 'OTHER')].Teacher | []
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这将给出:
[
{
"@id": "XYZ_1",
"TeacherType": {
"@tc": "5",
"#text": "GENDER"
},
"Gender": "FEMALE",
"Extension": {
"@VC": "23",
"Extension_Teacher": {
"DateDuration": {
"@tc": "10023111",
"#text": "0-6 MONTHS"
}
}
}
},
{
"@id": "XYZ_2",
"TeacherType": {
"@tc": "23",
"#text": "EDUCATED"
},
"Extension": {
"@VC": "23",
"Extension_Teacher": {
"DateDuration": {
"@tc": "10023111",
"#text": "CURRENT"
}
}
}
}
]
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