在 Kafka ksqlDB 上连接两个表时出现错误“无效连接条件：表-表连接需要连接正确输入表的主键”

Question

我需要从其他九个主题的组合中创建一个 Kafka 主题，所有主题均由 Debezium PostgreSQL 源连接器以 AVRO 格式生成。首先，我尝试（到目前为止未成功）组合来自两个主题的字段。

因此，首先根据“REQUEST”主题创建一个 ksqlDB 表：

ksql> CREATE TABLE TB_REQUEST (ID STRUCT<REQUEST_ID BIGINT> PRIMARY KEY)
         WITH (KAFKA_TOPIC='REQUEST', FORMAT='AVRO');

对我来说一切都很好：

ksql> DESCRIBE TB_REQUEST;

Name                 : TB_REQUEST
 Field       | Type
-----------------------------------------------------------------------------------------------------------------------

 ID          | STRUCT<REQUEST_ID BIGINT> (primary key)

 BEFORE      | STRUCT<REQUEST_ID BIGINT, REQUESTER_ID INTEGER, STATUS_ID>

 AFTER       | STRUCT<REQUEST_ID BIGINT, REQUESTER_ID INTEGER, STATUS_ID>
 
 SOURCE      | STRUCT<VERSION VARCHAR(STRING), CONNECTOR VARCHAR(STRING), NAME VARCHAR(STRING), TS_MS BIGINT, SNAPSHOT VARCHAR(STRING), DB VARCHAR(STRING), SEQUENCE VARCHAR(STRING), SCHEMA VARCHAR(STRING), TABLE VARCHAR(STRING), TXID BIGINT, LSN BIGINT, XMIN BIGINT>

 OP          | VARCHAR(STRING)

 TS_MS       | BIGINT

 TRANSACTION | STRUCT<ID VARCHAR(STRING), TOTAL_ORDER BIGINT, DATA_COLLECTION_ORDER BIGINT>

-----------------------------------------------------------------------------------------------------------------------
For runtime statistics and query details run: DESCRIBE <Stream,Table> EXTENDED;

然后我从“EMPLOYEE”主题创建另一个表：

ksql> CREATE TABLE TB_EMPLOYEE (ID STRUCT<EMPLOYEE_ID INT> PRIMARY KEY)
         WITH (KAFKA_TOPIC='EMPLOYEE', FORMAT='AVRO');

再次，一切似乎都很好。

ksql> DESCRIBE TB_EMPLOYEE;

Name                 : TB_EMPLOYEE
 Field       | Type                                                       
-----------------------------------------------------------------------------------------------------------------------
 ID          | STRUCT<EMPLOYEE_ID INTEGER> (primary key)

 BEFORE      | STRUCT<EMPLOYEE_ID INTEGER, NAME VARCHAR(STRING), HIRING_DATE DATE>
 
 AFTER       | STRUCT<EMPLOYEE_ID INTEGER, NAME VARCHAR(STRING), HIRING_DATE DATE>
 
 SOURCE      | STRUCT<VERSION VARCHAR(STRING), CONNECTOR VARCHAR(STRING), NAME VARCHAR(STRING), TS_MS BIGINT, SNAPSHOT VARCHAR(STRING), DB VARCHAR(STRING), SEQUENCE VARCHAR(STRING), SCHEMA VARCHAR(STRING), TABLE VARCHAR(STRING), TXID BIGINT, LSN BIGINT, XMIN BIGINT>

 OP          | VARCHAR(STRING)

 TS_MS       | BIGINT

 TRANSACTION | STRUCT<ID VARCHAR(STRING), TOTAL_ORDER BIGINT, DATA_COLLECTION_ORDER BIGINT>

-----------------------------------------------------------------------------------------------------------------------
For runtime statistics and query details run: DESCRIBE <Stream,Table> EXTENDED;

但是，通过尝试创建我的目标表，通过员工 ID 加入以前的目标表。

ksql> CREATE TABLE REQUEST_EMPLOYEE AS 
         SELECT RQ.ID->REQUEST_ID, RQ.AFTER->REQUESTER_ID, RQ.AFTER->STATUS_ID, EM.ID->EMPLOYEE_ID, EM.AFTER->NAME AS REQUESTER
         FROM TB_REQUEST RQ
         JOIN TB_EMPLOYEE EM ON RQ.AFTER->REQUESTER_ID = EM.ID->EMPLOYEE_ID;

我收到以下错误：

Could not determine output schema for query due to error: Invalid join condition: table-table joins require to join on the primary key of the right input table. Got RQ.AFTER->REQUESTER_ID = EM.ID->EMPLOYEE_ID.
Statement: CREATE TABLE REQUEST_EMPLOYEE WITH (KAFKA_TOPIC='REQUEST_EMPLOYEE', PARTITIONS=1, REPLICAS=1) AS SELECT
  RQ.ID->REQUEST_ID REQUEST_ID,
  RQ.AFTER->REQUESTER_ID REQUESTER_ID,
  RQ.AFTER->STATUS_ID STATUS_ID,
  EM.ID->EMPLOYEE_ID EMPLOYEE_ID,
  EM.AFTER->NAME REQUESTER
FROM TB_REQUEST RQ
INNER JOIN TB_EMPLOYEE EM ON ((RQ.AFTER->REQUESTER_ID = EM.ID->EMPLOYEE_ID))
EMIT CHANGES;

查看“DESCRIBE TB_EMPLOYEE”命令的输出，在我看来“EM.ID->EMPLOYEE_ID”是正确的选择。我缺少什么？

提前致谢。

PS：ksqlDB版本为0.21.0

Answer 1

我认为你应该在连接语句中至少使用一个行键，在以前版本的 KsqlDB 中连接表的唯一方法是通过行键，在当前版本 0.21.0 中可以使用外键。

检查以下示例：

CREATE TABLE orders_with_users AS
SELECT * FROM orders JOIN users ON orders.u_id = users.u_id EMIT CHANGES;

其中 u_id 被定义为主键，因此是行键。

CREATE TABLE users (
    u_id VARCHAR PRIMARY KEY
    name VARCHAR
  ) WITH (
    kafka_topic = 'users',
    partitions = 3,
    value_format = 'json'
  );

下面这句话也是类似的

CREATE TABLE orders_with_users AS
    SELECT * FROM orders JOIN users ON orders.u_id = users.ROWKEY EMIT CHANGES;

另一个观察结果是，KsqlDB 正在将 TB_EMPLOYE 的键视为 STRUCT<EMPLOYEE_ID INTEGER>，而不仅仅是整数。然后正在等待结构之间的比较。（具有相同的架构）

然后您可以执行以下步骤来创建表。

CREATE STREAM STREAM_EMPLOYEE (ID STRUCT<EMPLOYEE_ID INT> KEY)
         WITH (KAFKA_TOPIC='EMPLOYEE', FORMAT='AVRO');

CREATE STREAM STREAM_REKEY_EMPLOYEE 
AS SELECT ID->EMPLOYEE_ID employee_id, * FROM STREAM_EMPLOYEE
PARTITION BY ID->EMPLOYEE_ID
EMIT CHANGES;


CREATE TABLE TB_EMPLOYEE (employee_id PRIMARY KEY)
         WITH (KAFKA_TOPIC='STREAM_REKEY_EMPLOYEE', FORMAT='AVRO');

并使用employee_id字段加入，尝试使用你的主键作为原始类型。