import java.util.Scanner;
public class Nc3 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter time of arrival: ");
double time = input.nextDouble();
int arrivalTime;
arrivalTime = 0;
arrivalTime += time;
if (time % 20 != 0) {
time %= 20;
time = 20 - time;
System.out.println(arrivalTime +time);
}
else if (((arrivalTime + time) % 100) == 60.0) {
time += 40;
System.out.println(arrivalTime + time);
}
else
System.out.println("Now - " +arrivalTime);
}
}
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我被要求编写一个程序,获取当前时间的输入,并返回下一趟公交车发车的时间,知道公交车每 20 分钟在 00、20、40 发车,问题是,如果我输入 2243代表 22:43 我会返回 2260 而不是 2300
我建议您使用java.time.Duration它以ISO-8601 标准为模型,并作为JSR-310 实现的一部分随Java-8一起引入。
演示:
import java.time.Duration;
import java.time.LocalTime;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter time of arrival: ");
showNextDepartureTime(input.nextLine());
}
static void showNextDepartureTime(String arrivalTime) {
Duration nextDeparture = Duration.between(LocalTime.MIN, LocalTime.parse(arrivalTime));
int remainder = nextDeparture.toMinutesPart() % 20;
if (remainder != 0)
nextDeparture = nextDeparture.minusMinutes(remainder).plusMinutes(20);
System.out.printf("The next departure is at %2d:%02d", nextDeparture.toHoursPart(),
nextDeparture.toMinutesPart());
}
}
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示例运行:
Enter time of arrival: 22:43
The next departure is at 23:00
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另一个示例运行:
Enter time of arrival: 22:00
The next departure is at 22:00
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正如 Lino 在他的评论if中所建议的,您可以按如下方式替换正文:
if (remainder != 0)
nextDeparture = nextDeparture.plusMinutes(20 - remainder);
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