替换URL中的参数值

Question

// Below are a number of strings which need ammending
$string = "www.development_test.php?action=show_development_crs&test1&test2";
$string = "www.development_test.php?action=show_rfw&test1";
$string = "www.development_test.php?action=show_development_crs";

我需要编写一个preg_replace()函数来替换" ="+" &" 之间的值,或者在底部字符串的情况下,在"="之后的所有内容,当&new不存在"newAction"时.

有没有人有任何想法？

这是我到目前为止尝试过的,但失败了:

public function test1()
{
    $action      = "newAction";
    $string      = "www.development_crs.php?action=show_development_crs&test1&test2";
    $pattern     = '/(action=)(.*)(&)/';
    $replacement = "action=$action&";

    $string = preg_replace($pattern, $replacement, $string);

    echo $string;
}

Answer 1

$action      = 'newAction';
$string      = 'www.development_crs.php?action=show_development_crs&test1&test2';
$pattern     = '/action=[^&]+(.*)/';
$replacement = "action=$action$1";

$string = preg_replace($pattern, $replacement, $string);
echo $string;

输出:

www.development_crs.php?action=newAction&test1&test2