Chr*_*ini 26 javascript jquery autocomplete tag-it
试图让tag-it与ajax调用一起使用.
到目前为止一切都有效.除此之外,我无法通过ajax调用分配tagSource.
在萤火虫中,'数据'正在返回:
["Ruby","Ruby On Rails"]
但是当我输入输入框时它没有显示出来.
$('.tags ul').tagit({
itemName: 'question',
fieldName: 'tags',
removeConfirmation: true,
availableTags: ["c++", "java", "php", "javascript", "ruby", "python", "c"],
allowSpaces: true,
// tagSource: ['foo', 'bar']
tagSource: function() {
$.ajax({
url: "/autocomplete_tags.json",
dataType: "json",
data: { term: 'ruby' },
success: function(data) {
console.log(data);
return data;
}
});
}
});
console.log(data)回报["Ruby", "Ruby On Rails"].
我在这里错过了什么吗？还有其他人上班吗？
Eki*_*kim 38
似乎这个问题很长一段时间都没有得到解答,我打赌你已经找到了解决办法,但对于那些没有在这里的人是我的答案:
当我从我的代码中复制时,这个凹痕搞得一团糟;)
<input type="hidden" name="tags" id="mySingleField" value="Apple, Orange" disabled="true">
Tags:<br>
<ul id="mytags"></ul>
<script type="text/javascript">
jQuery(document).ready(function() {
jQuery("#mytags").tagit({
singleField: true,
singleFieldNode: $('#mySingleField'),
allowSpaces: true,
minLength: 2,
removeConfirmation: true,
tagSource: function( request, response ) {
//console.log("1");
$.ajax({
url: "search.php",
data: { term:request.term },
dataType: "json",
success: function( data ) {
response( $.map( data, function( item ) {
return {
label: item.label+" ("+ item.id +")",
value: item.value
}
}));
}
});
}});
});
实际上你可以在一些自动完成的jQuery示例中找到"search.php".
<?php
$q = strtolower($_GET["term"]);
if (!$q) return;
$items = array(
"Great Bittern"=>"Botaurus stellaris",
"Little Grebe"=>"Tachybaptus ruficollis",
"Black-necked Grebe"=>"Podiceps nigricollis",
"Little Bittern"=>"Ixobrychus minutus",
"Black-crowned Night Heron"=>"Nycticorax nycticorax",
"Heuglin's Gull"=>"Larus heuglini"
);
function array_to_json( $array ){
if( !is_array( $array ) ){
return false;
}
$associative = count( array_diff( array_keys($array), array_keys( array_keys( $array )) ));
if( $associative ){
$construct = array();
foreach( $array as $key => $value ){
// We first copy each key/value pair into a staging array,
// formatting each key and value properly as we go.
// Format the key:
if( is_numeric($key) ){
$key = "key_$key";
}
$key = "\"".addslashes($key)."\"";
// Format the value:
if( is_array( $value )){
$value = array_to_json( $value );
} else if( !is_numeric( $value ) || is_string( $value ) ){
$value = "\"".addslashes($value)."\"";
}
// Add to staging array:
$construct[] = "$key: $value";
}
// Then we collapse the staging array into the JSON form:
$result = "{ " . implode( ", ", $construct ) . " }";
} else { // If the array is a vector (not associative):
$construct = array();
foreach( $array as $value ){
// Format the value:
if( is_array( $value )){
$value = array_to_json( $value );
} else if( !is_numeric( $value ) || is_string( $value ) ){
$value = "'".addslashes($value)."'";
}
// Add to staging array:
$construct[] = $value;
}
// Then we collapse the staging array into the JSON form:
$result = "[ " . implode( ", ", $construct ) . " ]";
}
return $result;
}
$result = array();
foreach ($items as $key=>$value) {
if (strpos(strtolower($key), $q) !== false) {
array_push($result, array("id"=>$value, "label"=>$key, "value" => strip_tags($key)));
}
if (count($result) > 11)
break;
}
echo array_to_json($result);
?>
小智 13
看看这个: 如何让tagSource与$ .ajax()一起使用？(来自tag-it的github问题列表).
这是一个例子:HTML文件:
<!doctype html>
<html lang="en">
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.2/jquery.min.js" type="text/javascript" charset="utf-8"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.12/jquery-ui.min.js" type="text/javascript" charset="utf-8"></script>
<script src="js/tag-it.js" type="text/javascript" charset="utf-8"></script>
<link rel="stylesheet" type="text/css" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1/themes/flick/jquery-ui.css">
<link href="css/jquery.tagit.css" rel="stylesheet" type="text/css">
<script type="text/javascript">
$(document).ready(function() {
$("#mytags").tagit({
tagSource: function(search, showChoices) {
$.ajax({
url: "auto.php",
data: {search: search.term},
success: function(choices) {
showChoices(choices);
}
});
}
});
});
</script>
</head>
<body>
<ul id="mytags">
<li>Tag1</li>
</ul>
</body>
</html>
(从[here] [1]获取tag-it.js文件)
这是PHP文件:
<?php
header('Content-type: application/json');
$q = $_GET["search"];
//check $q, get results from your database and put them in $arr
$arr[] = 'tag1';
$arr[] = 'tag2';
$arr[] = $q;
echo json_encode($arr);
?>
这些答案都没有对我有效,所以我想我会回来发布我的代码确实有效.
var tagThis = $(".tagit");
tagThis.tagit({
tagSource: function(search, showChoices) {
$.ajax({
url: "/tags/search",
data: { search: search.term },
dataType: "json",
success: function(data) {
var assigned = tagThis.tagit("assignedTags");
var filtered = [];
for (var i = 0; i < data.length; i++) {
if ($.inArray(data[i], assigned) == -1) {
filtered.push(data[i]);
}
}
showChoices(filtered);
}
});
}
});
此代码假定URL返回JSON编码的字符串(字符串数组).然后,它将过滤掉已在输入中选择的任何标记.所以它们不会在列表中重复出现.否则,这适合我.
感谢其他人让我走上了正确的道路.
小智 5
tagSource已被折旧.
只需使用:
<script>
$(document).ready(function(){
$("#tagit").tagit({
autocomplete: {
source: "your-php-file.php",
}
});
});
</script>
您可以将所有属性添加到此:
<script>
$(document).ready(function(){
$("#tagit").tagit({
allowSpaces: true,
singleFieldDelimiter: ';',
allowDuplicates: true,
autocomplete: {
source: "your-php-file.php",
}
});
});
</script>