C#BackgroundWorker取消检查点缩短

Question

有没有办法缩短我的 BackgroundWorker.CancellationPending 检查站？

例如,有没有办法return像下面的示例代码一样进行封装？:

//REAL CODE (CURRENTLY USE THIS)
if (this.TW.CancellationPending) 
    return; 

//PSEUDO REPLACEMENT CODE
this.CkPt(CurrentMethod); //PSEUDO USAGE 
    //^^^ PARAMETER IS A REFERENCE TO THE CURRENT METHOD, SIMILAR TO `this` FOR AN OBJECT  
//OR MAYBE AN EXTENSION METHOD WOULD LOOK CLEANER
CurrentMethod.CkPt(); //PSEUDO USAGE

private void CkPt(Method m) //PSEUDO METHOD
{
    /*
        POSSIBLY PERFORM OTHER CHECKPOINT TASKS HERE
    */
    if (this.TW.CancellationPending) 
        m.return/*FROM METHOD THAT CALLED ME*/;
}  

我试图使这样的多检查点情况更具可读性:

//PSUEDO METHOD 
//DO NOT TAKE THIS AS REPEATING CODE
//IT IS ONLY MEANT TO SHOW MULTIPLE USES OF THE SAME CHECKPOINT
//MY REAL TASK METHOD(S) CONTAIN MANY MANY MANY AREAS THAT DON'T REPEAT AND REQUIRE CHECKPOINTS  
public void FakeBWTask()
{
    if (this.TW.CancellationPending) 
        return; 

    foreach (var F1 in Fake1)
    {
        if (this.TW.CancellationPending) 
            return; 

        foreach (var F2 in Fake2)
        {   
            if (this.TW.CancellationPending) 
                return; 
            foreach (var F3 in Fake3)
            {
                if (this.TW.CancellationPending) 
                    return; 
            }
        }
    }
}

谢谢你的帮助!!

Answer 1

没有办法调用methodA来调用methodB并让methodB返回methodA(因为我们没有尾递归)

考虑使用像这样的迭代器.它可以在某些情况下工作,您可以在其中放置try/catch中间检查点.

public void FakeBWTask()
{
   if (this.TW.CancellationPending) 
      return; 
   foreach (object ignore in FakeBWTaskSteps())
   {
      // Other checkpoint logic here....
      if (this.TW.CancellationPending) 
          return; 
   }
}

private IEnumerable<object> FakeBWTaskSteps()
{
   Part1();
   yield return null; // Execute checkpoint logic.

   Part2();
   yield return null; // Execute checkpoint logic.

   Part3();
   yield return null; // Execute checkpoint logic.

   Part4();
   yield return null; // Execute checkpoint logic.

   // Do some other stuff.
   yield return null; // Execute checkpoint logic.

   // final stuff.  No looping here.
}