PHP代码动态评估

Question

想象一下,我们有2个文件,其中一个1.php使用以下代码调用:

<?php
    $hello = "Hello from 1";
?>

并2.php使用以下代码:

<?php
    function LoadPage( $page )
    {
        $f = fopen( $page, 'r+' );  
        $content = fread( $f, filesize($page) );
        fclose( $f );
        return $content;
    }

    function GetEvalContent( $content )
    {
        $var = "";
        ob_start();
        eval( "?>" . $content . "<?" );
        $var = ob_get_contents();
        ob_end_clean();
        return $var;
    }

    $hello = "hello from 2";

    echo $hello . '<br/>';

    $content = LoadPage( '1.php' );
    GetEvalContent( $content );

    echo $hello;
?>

那么它的2.php作用是加载内容1.php并评估其中的php代码.现在我要做的是在评估期间1.php,变量$ hello更改为"hello from 1".但是如果你执行2.php你总是得到:

"hello from 2"
"hello from 2"

而不是得到

"hello from 2"
"hello from 1"

有没有人遇到过这个问题,如果有的话,你会怎么解决？

Answer 1

有一种更容易的方法来做到这一点.使用PHP include.

1.PHP

<?php
   $hello = "Hello from 1";
?>

2.PHP

<?php
   $hello = "hello from 2";
   echo $hello;
   include '1.php';
   echo $hello;
?>

更新(未测试):

function includeFile($file){
  global $hello;  // Use the global variable $hello
                  // this will make the include sets $hello correctly
  ob_start();
  include $file;  // Remember any variables set here will be in this scope,
                  // not the global scope (unless you add them to the global line above)
  $var = ob_get_contents();  // This will contain anything echoed to the screen
                             // from the included file
  ob_end_clean();
  return $var;
}

$hello = "hello from 2";
echo $hello;
$file = '1.php';
$output = includeFile($file);
echo $hello;
echo $output;