如何获取唯一 ID 的运行总数

Question

我需要获取唯一 ID 的运行总数

select ID, min(date_time)
,case when ID is null then 0 else 1 end as New_ID
,SUM(New_ID) over (order by ID) as runningTotal_ID
          from Table1
          Group by 1

或者也许我可以直接数 select Id, count(Id) over (order by ID) as Running Total

但绑定这个它给了我 10000...计数但只有 200 个 ID

任何人都可以帮我吗！

Answer 1

您可以使用dense_rank()。。。假设您想要它们，id则按顺序分配：

select t1.*, dense_rank() over (order by id) as runningTotalId
from Table1 t1;

如果没有，您可以标记第一个并使用累积和：

select t1.*,
       sum(case when seqnum = 1 then 1 else 0 end) over (order by datetime) as runningTotalId
from (select t1.*, 
             row_number() over (partition by id order by datetime) as seqnum
      from table1 t1
     ) t