PHP不使用DOMDocument保存

Question

我们将从代码开始直接前进:

PHP:

<?php
    $newJaCourse = $_POST["ja-new-course"];
    $newJaSide = $_POST["ja-new-side"];
    $newEnCourse = $_POST["en-new-course"];
    $newEnSide = $_POST["en-new-side"];

    $doc = new DOMDocument('1.0','utf-8');
    $doc->formatOutput=true;
    $doc->preserveWhiteSpace=false;
    echo $doc->load("../../xml/daily_lunch.xml") . "Loaded <br />";

    $japanese = $doc->getElementsByTagName("japanese")->item(0);
    $jacourse = $japanese->getElementsByTagName("course")->item(0);
    $jaside = $japanese->getElementsByTagName("side")->item(0);
    $english = $doc->getElementsByTagName("english")->item(0);
    $encourse = $english->getElementsByTagName("course")->item(0);
    $enside = $english->getElementsByTagName("side")->item(0);

    $jacourse->nodeValue = $newJaCourse;
    $jaside->nodeValue = $newJaSide;
    $encourse->nodeValue = $newEnCourse;
    $enside->nodeValue = $newEnSide;

    $japanese->replaceChild($jacourse,$jacourse);
    $japanese->replaceChild($jaside,$jaside);
    $english->replaceChild($encourse,$encourse);
    $english->replaceChild($enside,$enside);

    echo $doc->save("../../xml/daily_lunch.xml") . "Done!";
?>

我精美的HTML表单:

        <h4>Change Today's Lunch Menu:</h4>
        <form method="post" action="scripts/lunchupdate.php" name="changelunch">
            <table>
                <tr>
                    <th>Japanese: Course</th>
                    <td><input type="textbox" name="ja-new-course" /></td>      
                </tr>
                <tr>
                    <th>Japanese: Side</th>
                    <td><input type="textbox" name="ja-new-side" /></td>        
                </tr>
                <tr>
                    <th>English: Course</th>
                    <td><input type="textbox" name="en-new-course" /></td>      
                </tr>
                <tr>
                    <th>English: Side</th>
                    <td><input type="textbox" name="en-new-side" /></td>        
                </tr>
            </table>
            <a href="javascript:" onclick="writeNewLunch()">Set Menu</a> |
            <a href="javascript:" onclick="document.changelunch.reset()">Reset Input</a>
        </form>

我当前的XML:

<?xml version="1.0" encoding="UTF-8"?>
<lunch featuredisabled="false">
    <japanese>
        <course>
            ????????????
        </course>
        <side>
            ???????
        </side>
    </japanese>
    <english>
        <course>
            Shrimp and Tomato Cream Pasta
        </course>
        <side>
            Ceasar Side Salad
        </side>
    </english>
</lunch>

尽管您可以说明其目的,但它是更改XML文件中的项目.目标是为双语餐厅提供每日午餐更新服务.我精彩的DOMDocument-> save(filename)虽然没有做杰克.

什么都没有返回,我的所有变量和变化都回响.我正在运行PHP5.我查看了phpinfo()并找到了所有XML要求的配置,打开并且没有完成工作.

此脚本输出的唯一内容是:

Loaded

Done!

Answer 1

文件名丢失.根据您应该拥有的PHP文档

$doc->save('myfile.xml');

你有权写入文件夹吗？