无法推断通用参数“T” - Swift 5.5

Question

我试图让用户登录，但收到以下错误：

Generic parameter 'T' could not be inferred

这是代码：

// Gets User signed-in
func getUser() async throws -> AuthUser {
    do {
        try await withUnsafeThrowingContinuation { continuation in
            if let user = Amplify.Auth.getCurrentUser() {
                continuation.resume(returning: user )
            }
        }
    } catch(let error) {
        print(error)
    }
}

这是为什么？

Answer 1

实际上我的电话一开始就不好，应该这样做：

    // Gets User signed-in
    func getUser() async throws -> AuthUser {
        return try await withCheckedThrowingContinuation { (continuation: CheckedContinuation<AuthUser, Error>) in
            if let user = Amplify.Auth.getCurrentUser() {
                continuation.resume(returning: user)
                return
            } else {
                signOut()
                continuation.resume(with: .failure(YourCustomEnumError_or_the_actual_error))
                return
            }
        }
    }

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