ian*_*dev 6 javascript firebase reactjs google-cloud-firestore
我得到了这个简单的表单,用于注册用户并将 uid 和电子邮件数据发送到 firestore 上的集合,我使用最新版本的 Firebase 9 w/ 模块化。身份验证工作得很好,但 firestore 部分却不行。它向我抛出一个错误:
TypeError: Cannot read properties of undefined (reading 'indexOf')
at Function.fromString (path.ts:229)
at Ac2 (reference.ts:374)
at Login.jsx:29
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我不知道这是什么意思,我试图按照“用户/(这里是 useruid)/所有用户数据”的顺序将注册用户的电子邮件和 uid 信息上传到 firestore,但会抛出该错误。
我留下我的代码:
import React, { useState, useEffect, useCallback } from 'react'
import { auth, db } from "../firebase"
import { createUserWithEmailAndPassword } from "firebase/auth";
import { collection, doc, addDoc, setDoc } from "firebase/firestore";
function Login() {
const [email, setEmail] = useState('')
const [pass, setPass] = useState('')
const [error, setError] = useState('')
const [userData, setUserData] = useState('')
const ProcessData = e => {
e.preventDefault()
registro()
}
const registro = useCallback(async() => {
try {
await createUserWithEmailAndPassword(auth, email, pass)
.then((userCredential) => {
const user = userCredential.user;
setUserData(user)
})
await addDoc(collection(db, 'users', userData.uid), {
email: userData.email,
uid: userData.uid
})
setEmail('')
setPass('')
setError('')
} catch (error) {
const errorCode = error.code;
const errorMessage = error.message;
setError(errorMessage)
console.log(error)
}
}, [email, pass, error, userData])
return (
<div>
<h3>Registro</h3>
<form onSubmit={ProcessData}>
<label>Email Adress</label>
<input
type="email"
placeholder="Email Address"
onChange={e => setEmail(e.target.value)}
value={email}
/>
<label>Password</label>
<input
type="password"
placeholder="Password"
onChange={e => setPass(e.target.value)}
value={pass}
/>
<button type="submit">Registrarse</button>
</form>
</div>
)
}
export default Login
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userData
添加文档时,您不一定需要从状态读取数据。尝试直接从返回的对象传递参数user
,这样任何路径段都doc()
不会是未定义的:
try {
const { user } = await createUserWithEmailAndPassword(auth, email, pass)
setUserData(user)
// db must not be undefined
// try console.log(db) to ensure it's a Firestore instance
await setDoc(doc(db, 'users', user.uid), {
// ^^^ ^^^<-- DocumentReference and not CollectionReference
email: user.email,
uid: user.uid
})
} catch (e) {
console.log(e)
}
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此外,您还传递了 2 个路径段,其中collection()
可能会返回错误,因为 CollectionReference 路径采用奇数个路径段。如果您希望用户的 UID 作为文档 ID,则使用setDoc
sinceaddDoc
将生成随机 ID。
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