.NET中的XmlSerializer与XmlSchemaForm.Unqualified

Question

鉴于以下代码:

using System;
using System.Xml.Schema;
using System.Xml.Serialization;

namespace XmlSerializationTest
{
    [XmlType(Namespace = "http://www.test.com")]
    public class Element
    {
        [XmlElement]
        public int X;
    }

    [XmlRoot(Namespace = "http://www.test.com")]
    public class Root
    {
        [XmlElement(Form = XmlSchemaForm.Unqualified)]
        public Element Element;
    }

    public static class Program
    {
        public static void Main(string[] args)
        {
            var root = new Root { Element = new Element { X = 1 } };
            var xmlSerializer = new XmlSerializer(typeof(Root));
            xmlSerializer.Serialize(Console.Out, root);
        }
    }
}

输出是:

<?xml version="1.0" encoding="ibm852"?>
<Root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://www.test.com">
  <Element xmlns="">
    <X xmlns="http://www.test.com">1</X>
  </Element>
</Root>

问题是为什么设置Form属性会XmlSchemaForm.Unqualified导致Element元素的命名空间被设置为""即使它具有XmlTypeAttribute与Root元素具有相同命名空间的属性？

这种代码(XmlSchemaForm.Unqualified部分)是由WSCF.blue工具生成的,它正在弄乱命名空间.

Answer 1

您可以覆盖元素类型中指定的命名空间。例如你可以有

[XmlElement(Namespace="http://foo.com")]
public Element Element;

输出将是

<Root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://www.test.com">
  <Element xmlns="http://foo.com">
    <X xmlns="http://www.test.com">1</X>
  </Element>
</Root>

Microsoft 的实现似乎与设置为Form = XmlSchemaForm.Unqualified完全相同。特别是，如果您明确指定任何其他命名空间（ MSDN 参考） ，则无法使用它。如果这样做，您将得到以下异常：Namespace""

Unhandled Exception: System.InvalidOperationException: There was an error reflecting type 'XmlSerializationTest.Root'. ---> System.InvalidOperationException: There was an error reflecting field 'Element'. ---> System.InvalidOperationException: The Form property may not be 'Unqualified' when an explicit Namespace property is present.