参数列表太长 - Unix

Question

此脚本将按日期对文件进行排序,然后将前2500个文件移动到另一个目录.
当我在脚本下面运行时,系统会提示输出参数列表太长时间.任何人都可以帮我增强脚本？谢谢

NUM_OF_FILES=2500
FROM_DIRECTORY=/apps/data01/RAID/RC/MD/IN_MSC/ERC/in
DESTINATION_DIRECTORY=/apps/data01/RAID/RC/MD/IN_MSC/ERC/in_load

if [ ! -d $DESTINATION_DIRECTORY ]  
        then  
                echo "unused_file directory does not exist!"  
        mkdir $DESTINATION_DIRECTORY   
        echo "$DESTINATION_DIRECTORY directory created!"  
else   
        echo "$DESTINATION_DIRECTORY exist!"    
fi  


echo "Moving $NUM_OF_FILES oldest files to $DESTINATION_DIRECTORY directory"  

ls -tr  $FROM_DIRECTORY/MSCERC*.Z|head -$NUM_OF_FILES |
    xargs -i sh -c "mv {} $DESTINATION_DIRECTORY"  

Answer 1

首先创建要处理的文件的备份列表。然后逐行读取备份文件并修复它。例如

 #!/bin/bash
 NUM_OF_FILES=2500
 FROM_DIRECTORY=/apps/data01/RAID/RC/MD/IN_MSC/ERC/in
 DESTINATION_DIRECTORY=/apps/data01/RAID/RC/MD/IN_MSC/ERC/in_load

 if [ ! -d $DESTINATION_DIRECTORY ]  
    then  
            echo "unused_file directory does not exist!"  
    mkdir $DESTINATION_DIRECTORY   
    echo "$DESTINATION_DIRECTORY directory created!"  
  else   
    echo "$DESTINATION_DIRECTORY exist!"    
 fi  

 echo "Moving $NUM_OF_FILES oldest files to $DESTINATION_DIRECTORY directory" 

 ls -tr  $FROM_DIRECTORY/MSCERC*.Z|head -2500 > list
 exec 3<list

 while read file <&3
 do
    mv $file $DESTINATION_DIRECTORY
 done