datagrid获取单元格索引

Question

是否有可能获取列标题="column4"并且行包含"232"的单元格索引,例如我上传的屏幕截图是否可以获得红色单元格索引而不是使其变为红色？如果wpf datagrid有这个功能,wpf工具包数据网格有吗？列和行是从代码后面添加的

Answer 1

您应该通过Style/ Trigger或Binding使用转换器来执行此操作

<DataGrid Name="dataGrid"
          ...>
    <DataGrid.Columns>
        <DataGridTextColumn Header="column4" Binding="{Binding column4}">
            <DataGridTextColumn.CellStyle>
                <Style TargetType="DataGridCell">
                    <Style.Triggers>
                        <DataTrigger Binding="{Binding column4}" Value="232">
                            <Setter Property="Background" Value="Red"/>
                        </DataTrigger>
                    </Style.Triggers>
                </Style>
            </DataGridTextColumn.CellStyle>
        </DataGridTextColumn>
        <!--...-->
    </DataGrid.Columns>
    <!--...-->
</DataGrid>

默认情况下,DataGrid正在使用虚拟化,因此只会DataGridRows加载此时用户可见的虚拟化.其他行将在可见后创建,因此如果您尝试在后面的代码中设置一些单元格可能会变得非常混乱(您尝试访问的单元格可能尚未存在.)

要获取DataGridCell索引行/列,您可以定义一个帮助器类(DataGridHelper)并像这样使用它

DataGridCell cell = DataGridHelper.GetCell(dataGrid, 0, 2);
if (cell != null)
{
    cell.Background = Brushes.Red;
}

DataGridHelper

static class DataGridHelper
{
    static public DataGridCell GetCell(DataGrid dg, int row, int column)
    {
        DataGridRow rowContainer = GetRow(dg, row);

        if (rowContainer != null)
        {
            DataGridCellsPresenter presenter = GetVisualChild<DataGridCellsPresenter>(rowContainer);

            // try to get the cell but it may possibly be virtualized
            DataGridCell cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
            if (cell == null)
            {
                // now try to bring into view and retreive the cell
                dg.ScrollIntoView(rowContainer, dg.Columns[column]);
                cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
            }
            return cell;
        }
        return null;
    }

    static public DataGridRow GetRow(DataGrid dg, int index)
    {
        DataGridRow row = (DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(index);
        if (row == null)
        {
            // may be virtualized, bring into view and try again
            dg.ScrollIntoView(dg.Items[index]);
            row = (DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(index);
        }
        return row;
    }

    static T GetVisualChild<T>(Visual parent) where T : Visual
    {
        T child = default(T);
        int numVisuals = VisualTreeHelper.GetChildrenCount(parent);
        for (int i = 0; i < numVisuals; i++)
        {
            Visual v = (Visual)VisualTreeHelper.GetChild(parent, i);
            child = v as T;
            if (child == null)
            {
                child = GetVisualChild<T>(v);
            }
            if (child != null)
            {
                break;
            }
        }
        return child;
    }
}