Django select_related与指定的字段分隔多个一对一关系

rfr*_*kel 5 django django-orm django-queryset django-select-related django-inheritance

我在尝试通过多个OneToOneField关系选择相关时遇到了一个奇怪的错误,例如在目标字段是孙子类的情况下.我希望有人帮助我了解正在发生的事情(或确认这是Django中的一个错误).

插图:

# models.py
from django.db import models

class A(models.Model):
    pass

class B(A):
    pass

class C(B):
    pass
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很简单吧?现在我用一个干净的数据库打开Django shell:

>>> C().save()
>>> A.objects.select_related('b__c')
[]
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等等,什么?为什么该查询集为空?快速健全检查:

>>> A.objects.select_related('b')[0].b.c
<C: C object>
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那么为什么select_related调用不起作用呢?好吧,看这个:

>>> A.objects.select_related('b__c').__iter__().next()
... 
Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "/opt/webapps/asdf/lib/python2.6/site-packages/django/db/models/query.py", line 107, in _result_iter
    self._fill_cache()
  File "/opt/webapps/asdf/lib/python2.6/site-packages/django/db/models/query.py", line 772, in _fill_cache
    self._result_cache.append(self._iter.next())
  File "/opt/webapps/asdf/lib/python2.6/site-packages/django/db/models/query.py", line 273, in iterator
    for row in compiler.results_iter():
  File "/opt/webapps/asdf/lib/python2.6/site-packages/django/db/models/sql/compiler.py", line 680, in results_iter
    for rows in self.execute_sql(MULTI):
  File "/opt/webapps/asdf/lib/python2.6/site-packages/django/db/models/sql/compiler.py", line 725, in execute_sql
    sql, params = self.as_sql()
  File "/opt/webapps/asdf/lib/python2.6/site-packages/django/db/models/sql/compiler.py", line 58, in as_sql
    self.pre_sql_setup()
  File "/opt/webapps/asdf/lib/python2.6/site-packages/django/db/models/sql/compiler.py", line 29, in pre_sql_setup
    self.fill_related_selections()
  File "/opt/webapps/asdf/lib/python2.6/site-packages/django/db/models/sql/compiler.py", line 661, in fill_related_selections
    used, next, restricted, new_nullable)
  File "/opt/webapps/asdf/lib/python2.6/site-packages/django/db/models/sql/compiler.py", line 617, in fill_related_selections
    chain = opts.get_base_chain(f.rel.to)
  File "/opt/webapps/asdf/lib/python2.6/site-packages/django/db/models/options.py", line 452, in get_base_chain
    % model._meta.module_name,)
TypeError: 'b' is not an ancestor of this model
>>> 
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那么,这是一个Django错误,还是我不理解某些东西?

j_s*_*syk 0

我将 name=CharField 添加到 A 并在 shell 中运行以下测试:

>>> a = A(name='a_object')
>>> a.save()
>>> b = B(name='b_object')
>>> b.save()
>>> c = C(name='c_object')
>>> c.save()

>>> A.objects.all()
[<A: A object>, <A: A object>, <A: A object>]
>>> B.objects.all()
[<B: B object>, <B: B object>]
>>> C.objects.all()
[<C: C object>]

>>> A.objects.select_related('b__c')
[]
>>> A.objects.select_related('b__c').__iter__().next()
Traceback ....
    ...
    TypeError: 'b' is not an ancestor of this model

>>> d = A.objects.select_related('B__C')
>>> for item in d:
...     print item.name
... 
a_object
b_object
c_object

>>> test = A.objects.select_related('B__C').__iter__().next()
>>> test.name
u'a_object'
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我知道这不是一个答案,我也不知道该怎么办。但基本上我发现小写字母似乎在模型中没有字段的情况下没有任何意义。