C 中的嵌套 if 语句 - 为什么它不评估最后一个 else if？

Question

else if当您分配给choicevalue时，以下代码不会执行最后一条语句3。

#include<stdio.h>
#include<stdlib.h>

int main() {
    puts("Specify with a number what is that you want to do.");
    puts("1. Restore wallet from seed.");
    puts("2. Generate a view only wallet.");
    puts("3. Get guidance on the usage from within monero-wallet-cli.");

    unsigned char choice;
    choice = getchar(); 
 
    if ( choice == '1' ) {
        system("nice -19 ~/monero-x86_64-linux-gnu-v0.17.2.0/monero-wallet-cli --testnet --restore-deterministic-wallet"); 
        exit(0);
    }
    else if ( choice == '2' ) {
        system("nice -19 ~/monero-x86_64-linux-gnu-v0.17.2.0/monero-wallet-cli --testnet --generate-from-view-key wallet-view-only");
        exit(0);
    }
    else if ( choice == '3' ) {    
        puts("Specify with a number what is that you want to do.");
        puts("1. Get guidance in my addresses and UTXOs");
        puts("2. Pay");
        puts("3. Get guidance on mining.");
    
        unsigned char choicetwo = getchar();
        if ( choicetwo == '1' ) {      
            printf("Use \033address all\033 to get all your addresses that have any balance, or that you have generated at this session.");
            printf("Use \033balance\033 to get your balance");
            printf("Use \033show_transfers\033 to get ");
            printf("Use \033show_transfers\033 out to get ");
            printf("Use \033show_transfers in\033 to get your balance");
        }
    }

    return 0;   
}

当我输入时，我得到以下输出3：

Specify with a number what is that you want to do.
1. Restore wallet from seed.
2. Generate a view only wallet.
3. Get guidance on the usage from within monero-wallet-cli.
3
Specify with a number what is that you want to do.
1. Get guidance in my addresses and UTXOs
2. Pay
3. Get guidance on mining.

我真的被阻止了，有些东西丢失了，我不知道为什么它不继续第二次接受用户的输入。

Answer 1

当您为第一个输入输入“3”时，您实际上是在输入两个字符：字符'3'和换行符。第一个getchar函数从输入流中读取“3”，第二个函数读取换行符。

接受第一个输入后，您需要getchar循环调用，直到读取换行符以清除输入缓冲区。

choice = getchar();
while (getchar() != '\n');