关于索引器和/或泛型的问题

Question

如何知道对象是否实现索引器？我需要共享DataRow和IDataReader的逻辑,但它们不共享任何接口.

我也尝试使用泛型,但不知道我应该对where子句施加什么限制.

public class Indexer {
    // myObject should be a DataRow or a IDataReader
    private object myObject;
    public object MyObject {
        get { return myObject; }
        set { myObject = value; }
    }
    // won't compile, myObject has no indexer
    public object this[int index] {
        get { return myObject[index]; }
        set { myObject[index] = value; }
    }
    public Indexer(object myObject) {
        this.myObject = myObject;
    }
}

public class Caller {
    void Call() {
        DataRow row = null;
        IDataReader reader = null;
        var ind1 = new Indexer(row);
        var ind2 = new Indexer(reader);
        var val1 = ind1[0];
        var val2 = ind1[0];
    }
}

Answer 1

您需要声明具有索引器属性的接口,使用该接口作为约束,并且类型参数类需要实现该接口以满足约束.

由于您无法控制要使用的类,因此无效.

另一种方法是使Indexer类将get/set操作作为单独的参数:

public class Indexer {

    private Func<int, object> getter;        
    private Action<int, object> setter;

    public object this[int index] 
    {
        get { return getter(index); }
        set { setter(index, value); }
    }

    public Indexer(Func<int, object> g, Action<int, object> s) 
    {
        getter = g;
        setter = s;
    }
}

public static class IndexerExtensions
{
    public static Indexer ToIndexer(this DataRow row)
    {
        return new Indexer(n => row[n], (n, v) => row[n] = v);
    }

    public static Indexer ToIndexer(this IDataReader row)
    {
        return new Indexer(n => row[n], (n, v) => row[n] = v);
    }
}

然后你可以这样做:

DataRow row = null;
IDataReader reader = null;
var ind1 = row.ToIndexer();
var ind2 = reader.ToIndexer();
var val1 = ind1[0];
var val2 = ind1[0];