Oracle SQL将HEX转换为char

Question

我试图十六进制转换为字符在甲骨文非常像这样为Microsoft SQL Server

select xx('0A') from dual;

这里0A是十六进制UNIX中换行符.

Answer 1

尝试

SELECT UTL_I18N.RAW_TO_CHAR (<string>, <src_char_set>) FROM DUAL; 

例如,

SELECT UTL_I18N.RAW_TO_CHAR ('0A', 'AL32UTF8') FROM DUAL;