C++中的析构函数和继承？

Question

我使用Borland C++ Builder.

我有问题

#include <Classes.hpp>
class TMyObject : public TObject
{
   __fastcall TMyObject();
   __fastcall ~TMyObject();//I would like to inherite my destructor from TObject
};

__fastcall TMyObject::TMyObject() : TObject()//it will inherited my constructor from TObject
{
}

对于那个将继承的新析构函数~TObject？

__fastcall TMyObject::~TMyObject?????????????

Answer 1

TObject这个可以在s层面解决。它的析构函数必须是虚拟的：

#include <Classes.hpp>
class TObject 
{
   __fastcall TObject();
   virtual __fastcall ~TObject(); 
};

这样你可以这样做：

TObject * pobj = new TMyObject();
delete pobj;

或者

TMyObject * pobj = new TMyObject();
delete pobj;

两个析构函数都会被调用（~TMyObject()首先然后然后~TObject()），并且不会有泄漏。