djangorest框架通过id更新嵌套序列化器

afr*_*afr 2 python django django-rest-framework

如何通过 id 更新嵌套序列化器中的列表

我的用户有多个联系人

例子:

接触串行器

class ContactSerializer(serializers.ModelSerializer):
    class Meta:
        model = Contact
        fields = [
            'id',
            'name',
            'last_name'
        ]
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用户序列化器

class UserSerializer(serializers.ModelSerializer):
    email = serializers.EmailField(
        required=True,
        validators=[
            UniqueValidator(queryset=User.objects.all())
        ]
    )
    contacts = ContactSerializer(many=True)

    class Meta:
        model = User
        fields = [
            "email",
            "contacts"
        ]


    def update(self, instance, validated_data):
        contacts_data = validated_data.pop('contacts')
        contacts = (instance.contacts).all()
        contacts = list(contacts)
        instance.name = validated_data.get('name', instance.name)
        instance.save()

        # many contacts
        for contact_data in contacts_data:
            contact = contacts.pop(0)
            contact.name = contact_data.get('name', contact.name)
            contact.last_name = contact_data.get('last_name', contact.last_name)
            contact.save()

        return instance
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我想按 ID 更新联系人,目前可以,但它只更新列表中的第一个联系人

示例我想更新 ID 为 4 和 6 的联系人

负载请求

{
    "name": "string",
    "contacts": [
        {
            "id": 4, 
            "name": "string",
            "last_name": "string"
        },
        {
            "id": 6, 
            "name": "string",
            "last_name": "string"
        }
    ]
}
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有什么想法或建议吗?

Jim*_*mar 7

像这样尝试一下

def update(self, instance, validated_data):
        contacts_data = validated_data.pop('contacts')

        instance.name = validated_data.get('name', instance.name)
        instance.save()

        # many contacts
        for contact_data in contacts_data:
            contact = Contact.objects.get(pk=contact_data['id']) # this will crash if the id is invalid though
            contact.name = contact_data.get('name', contact.name)
            contact.last_name = contact_data.get('last_name', contact.last_name)
            contact.save()

        return instance
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