我正在尝试理解shell/bash脚本,只是想$?在代码中使用输入.它与函数调用一起使用.
功能示例:
function showerr { err=$1
if [ $err -ne 0 ]; then
echo `date` : "error!"
echo "stat : " $2
echo `date` : "stat: " $2
# alert email
prog=$0
uname=`whoami`
echo `date` : Sending email to ${ADDR_TO}
mailx -s "Error checking status " $ADDR_TO << EOF
+++++++++++++++++++++
stat = $2
util = $prog
host = $uname
+++++++++++++++++++++
Check $uname for details.
.
EOF
echo "Exiting program..."
exit 1
fi
}
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这里有一些陈述showerr.我看到一些条件(使用1或任何数字的值)和一些只是调用它$?.
if [[ $Res = *"FileNotFound"* ]]
then
echo `date` : Msg here
showerr 1 "Msg details here"
else
echo `date` : File: <filename> found.
fi
echo `date` : Msg detail here
flsz=`echo $size | cut -d'"' -f2`
showerr $? "error getting size for: (${flsz})"
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$?是最后一个命令的退出代码.有关POSIX shell中此类特殊变量的列表,请参阅Shell命令语言:特殊参数.
showerr如果第一个参数不是,该函数会记录错误0.
所以:
./some_super_script_that_might_fail
showerr $? "SuperScript failed"
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如果./some_super_script_that_might_fail退出代码不为0(传统意味着它失败),它将只记录一些东西.
showerr 1 "message"
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将永远记录.
showerr 0 "message"
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永远不会做任何事情.