我正在尝试实现 Facebook、Google 和 Twitter 身份验证。到目前为止,我已经在各自的开发者平台中设置了应用程序,将这些密钥/秘密添加到我的 Supabase 控制台,并创建了此 graphql 解析器:
/* eslint-disable @typescript-eslint/explicit-module-boundary-types */
import camelcaseKeys from 'camelcase-keys';
import { supabase } from 'lib/supabaseClient';
import { LoginInput, Provider } from 'generated/types';
import { Provider as SupabaseProvider } from '@supabase/supabase-js';
import Context from '../../context';
import { User } from '@supabase/supabase-js';
export default async function login(
_: any,
{ input }: { input: LoginInput },
{ res, req }: Context
): Promise<any> {
const { provider } = input;
// base level error object
const errorObject = {
__typename: 'AuthError',
};
// return error object if no provider is given
if (!provider) {
return {
...errorObject,
message: 'Must include provider',
};
}
try {
const { user, session, error } = await supabase.auth.signIn({
// provider can be 'github', 'google', 'gitlab', or 'bitbucket'
provider: 'facebook',
});
console.log({ user });
console.log({ session });
console.log({ error });
if (error) {
return {
...errorObject,
message: error.message,
};
}
const response = camelcaseKeys(user as User, { deep: true });
return {
__typename: 'LoginSuccess',
accessToken: session?.access_token,
refreshToken: session?.refresh_token,
...response,
};
} catch (error) {
return {
...errorObject,
message: error.message,
};
}
}
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我在该函数的正下方设置了三个控制台日志signIn(),所有这些日志都返回 null。
我还可以直接访问https://<your-ref>.supabase.co/auth/v1/authorize?provider=<provider>并且身份验证工作正常,因此它似乎已专门缩小到该signIn()功能。什么会导致响应返回空值?
发生这种情况是因为这些值只有在 OAuth 服务器重定向之后才会填充。如果您查看supabase/gotrue-js的内部代码,您将看到null显式返回。
private _handleProviderSignIn(
provider: Provider,
options: {
redirectTo?: string
scopes?: string
} = {}
) {
const url: string = this.api.getUrlForProvider(provider, {
redirectTo: options.redirectTo,
scopes: options.scopes,
})
try {
// try to open on the browser
if (isBrowser()) {
window.location.href = url
}
return { provider, url, data: null, session: null, user: null, error: null }
} catch (error) {
// fallback to returning the URL
if (!!url) return { provider, url, data: null, session: null, user: null, error: null }
return { data: null, user: null, session: null, error }
}
}
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流程是这样的:
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