将Boost FileSystem3迭代器转换为const char *

Question

我正在使用Boost FileSystem 3遍历目录中的某些文件，并且需要将文件名转换为另一个库的char *，不幸的是我缺少C ++ foo，有人可以帮忙吗？

  int main(int argc, char* argv[])
    {
      path p (argv[1]);   // p reads clearer than argv[1] in the following code

      try
      {
        if (exists(p))    // does p actually exist?
        {
          if (is_regular_file(p))        // is p a regular file?   
            cout << p << " size is " << file_size(p) << '\n';

          else if (is_directory(p))      // is p a directory?
          {
            cout << p << " is a directory containing:\n";

            typedef vector<path> vec;             // store paths,
            vec v;                                // so we can sort them later

            copy(directory_iterator(p), directory_iterator(), back_inserter(v));

            sort(v.begin(), v.end());             // sort, since directory iteration
                                                  // is not ordered on some file systems

            for (vec::const_iterator it (v.begin()); it != v.end(); ++it)
            {
              cout << "   " << *it << '\n';
       /****************** stuck here **************************/
      // I need to cast *it to a const char* filename 
       /****************** stuck here **************************/
            }
          }

          else
            cout << p << " exists, but is neither a regular file nor a directory\n";
        }
        else
          cout << p << " does not exist\n";
      }

      catch (const filesystem_error& ex)
      {
        cout << ex.what() << '\n';
      }

      return 0;
    }

Answer 1

该表达式*it返回一个类型的对象path，所以你必须这样做：

const std::string & s = (*it).string(); 
const char *str = s.c_str(); //this is what you want

或者您可能想使用其他转换函数，如下所示：

const std::string & string() const;
std::string native_file_string() const;
std::string native_directory_string() const;

选择您想使用的任何一个。首先阅读文档了解它们各自返回的内容：

• 升压/文件系统/path.hpp