使用JDBC连接从oracle返回插入语句的ROWID参数

Question

我似乎无法获得正确的魔法组合来完成这项工作:

OracleDataSource ods = new oracle.jdbc.pool.OracleDataSource();
ods.setURL("jdbc:oracle:thin:app_user/pass@server:1521:sid");
DefaultContext conn = ods.getConnection();
CallableStatement st = conn.prepareCall("INSERT INTO tableA (some_id) VALUES (1) RETURNING ROWID INTO :rowid0");
st.registerReturnParameter(1, OracleTypes.ROWID);
st.execute();

我得到的错误是"违反协议".如果我更改为registerOutParameter(),我会收到通知我没有注册所有返回变量.如果我将语句包装在PL/SQL中开始; 结束; 然后我使用常规registerOutParameter()调用得到参数.我真的更愿意避免在PL/SQL中包装所有的insert语句 - 那么上面缺少什么？

Answer 1

通常,您不希望依赖于代码数据库.您应该使用CallableStatement而不是OraclePreparedStatement.

CallableStatement statement = connection.prepareCall("{call INSERT INTO tableA (some_id) VALUES (1) RETURNING ROWID INTO ? }");
statement.registerOutParameter( 1, Types.VARCHAR );

int updateCount = statement.executeUpdate();
if (updateCount > 0) {
   return statement.getString(1);
}

Answer 2

你需要做的一些事情

• 将CallableStatement更改为OracleCallableStatement
• 尝试并返回NUMBER,即:OracleTypes.Number

从查询返回信息的示例代码:

OraclePreparedStatement pstmt = (OraclePreparedStatement)conn.prepareStatement(
       "delete from tab1 where age < ? returning name into ?");
pstmt.setInt(1,18);

/** register returned parameter
  * in this case the maximum size of name is 100 chars
  */
pstmt.registerReturnParameter(2, OracleTypes.VARCHAR, 100);

// process the DML returning statement
count = pstmt.executeUpdate();
if (count>0)
{
  ResultSet rset = pstmt.getReturnResultSet(); //rest is not null and not empty
  while(rset.next())
  {
    String name = rset.getString(1);
    ...
  }
}

有关Oracle JDBC扩展的更多信息:

• http://download-uk.oracle.com/docs/cd/B19306_01/java.102/b14355/oraint.htm