当参数作为对象传递时的 Typescript 构造函数简写

Question

我知道当我们以传统方式传递参数时，我们可以使构造函数简写

class Foo {
  
  private name: string;
  private age: number;

  constructor(name: string, age: number) {
    this.name = name;
    this.age= age;
  }
}

因此，此类的等效简写构造函数符号将是

class Foo {
      constructor(private name: string, private age: number) {}
    }

同样，当构造函数参数作为对象传递时，我该如何做相同的简写，如下所示。

    class Foo {
      private name: string;
      private age: number;
      private group: string;
      constructor({
        name,
        age,
        group,
      }: {
        name: string;
        age: number;
        group: string;
      }) {
        this.name= name;
        this.age= age;
        this.group= group;
      }
   }

Answer 1

你可以这样做：

  class Foo {
      constructor(public obj : { name: string, age: number, group: string}) {
      }
   }
  let foo = new Foo({name: 'name',  age: 42, group: 'answers'});

  alert(foo.obj.name);

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