Bor*_*aev -2 python dictionary list
我有一本字典,以问题为键,以答案选项列表为值。
quiz = {
'Question 1': ['yes', 'no'],
'Question 2': ['dogs', 'cats'],
'Question 3': ['apples', 'oranges']
}
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获得所有可能的答案组合的最佳方法是什么?
事实上2**3,你可以得到8 种可能性itertools.product
from itertools import product
quiz = {
'Question 1': ['yes', 'no'],
'Question 2': ['dogs', 'cats'],
'Question 3': ['apples', 'oranges']
}
for responses in product(*quiz.values()):
print(responses)
# each row is a tuple
('yes', 'dogs', 'apples')
('yes', 'dogs', 'oranges')
('yes', 'cats', 'apples')
('yes', 'cats', 'oranges')
('no', 'dogs', 'apples')
('no', 'dogs', 'oranges')
('no', 'cats', 'apples')
('no', 'cats', 'oranges')
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