C++ 中的动态数组实现

use*_*585 0 c++ class definition member-functions dynamic-memory-allocation

我正在尝试使用 C++ 实现动态数组。但是,我的resize()功能似乎无法正常工作。没有错误或警告。我做了一些研究并尝试查看互联网上找到的其他实现,但无法解决该问题。我把我的代码放在下面。

#include <iostream>

class Array
{
private:
    int* arr;
    int size = 0;
    int capacity = 1;

public:
    Array() { arr = new int[capacity]; }

    Array(int capacity)
        :
        capacity(capacity)
    {
        arr = new int[capacity];
    }

    int length() const { return size; }

    bool is_empty() const { return (length() == 0); }

    int get(int index) const { return arr[index]; }

    void set(int index, int value) { arr[index] = value; }

    void resize()
    {
        capacity *= 2;
        int* temp = new int[capacity];
        for (int i = 0; i < size; i++) { temp[i] = arr[i]; }
        delete[] arr;
        arr = temp;
        for (int i = 0; i < capacity; i++) { arr[i] = 0; }
    }

    void add(int value)
    {
        if (size + 1 >= capacity) { resize(); }
        arr[size++] = value;
    }

    void remove(int index)
    {
        for (int i = index; i < size - 1; i++)
        {
            arr[i] = arr[i + 1];
        }
        size--;
    }

    int& operator[](int index)
    {
        return arr[index];
    }
};

int main()
{
    Array array;

    for (int i = 0; i < 5; i++)
    {
        array.add(i + 1);
    }

    for (int i = 0; i < array.length(); i++)
    {
        std::cout << array.get(i) << " ";
    }
    std::cout << '\t' << array.length() << '\n';

    return 0;
}
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代码输出:

#include <iostream>

class Array
{
private:
    int* arr;
    int size = 0;
    int capacity = 1;

public:
    Array() { arr = new int[capacity]; }

    Array(int capacity)
        :
        capacity(capacity)
    {
        arr = new int[capacity];
    }

    int length() const { return size; }

    bool is_empty() const { return (length() == 0); }

    int get(int index) const { return arr[index]; }

    void set(int index, int value) { arr[index] = value; }

    void resize()
    {
        capacity *= 2;
        int* temp = new int[capacity];
        for (int i = 0; i < size; i++) { temp[i] = arr[i]; }
        delete[] arr;
        arr = temp;
        for (int i = 0; i < capacity; i++) { arr[i] = 0; }
    }

    void add(int value)
    {
        if (size + 1 >= capacity) { resize(); }
        arr[size++] = value;
    }

    void remove(int index)
    {
        for (int i = index; i < size - 1; i++)
        {
            arr[i] = arr[i + 1];
        }
        size--;
    }

    int& operator[](int index)
    {
        return arr[index];
    }
};

int main()
{
    Array array;

    for (int i = 0; i < 5; i++)
    {
        array.add(i + 1);
    }

    for (int i = 0; i < array.length(); i++)
    {
        std::cout << array.get(i) << " ";
    }
    std::cout << '\t' << array.length() << '\n';

    return 0;
}
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但我希望它输出:

0 0 0 4 5   5
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Cor*_*mer 5

在您的resize方法中,您复制了现有元素arr

for (int i = 0; i < size; i++) { temp[i] = arr[i]; }
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但后来你0把所有的元素都拿出来,有效地清除了以前的数据

for (int i = 0; i < capacity; i++) { arr[i] = 0; }
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相反,您可能只想要0尾随的新元素

for (int i = size; i < capacity; ++i) { arr[i] = 0; }
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