table a
-------------------------------------------------
id name wishlist1 wishlist2 wishlist3
1 john 1 2 3
2 paul 4 5
table b
--------------------------------------------------
id goods
1 car
2 aircraft
3 bicycle
4 motorbike
5 ipad
result i want to get
---------------------------------------------------
john car aircraft bicycle
paul motorbike ipad
Run Code Online (Sandbox Code Playgroud)
我怎么能得到这个结果?(在mysql中)
这最多可输出3个愿望(如果没有愿望,则在愿望列中显示空值)
select
name,
g1.goods as wish1,
g2.goods as wish2,
g3.goods as wish3
from tablea a
left join tableb g1.id on g1.wishlist1
left join tableb g2.id on g1.wishlist2
left join tableb g3.id on g1.wishlist3
Run Code Online (Sandbox Code Playgroud)
这可能会更好,如果你不介意以逗号分隔的愿望清单,那就更好了:
select
name,
group_concat(goods) as wishes
from tablea a
left join tableb b on b.id in (a.wishlist1, a.wishlist2, a.wishlist3)
group by name;
Run Code Online (Sandbox Code Playgroud)
这将输出:
name | wishes
------|----------------------
john | car,aircraft,bicycle
paul | motorbike,ipad
Run Code Online (Sandbox Code Playgroud)