将数据帧转换为元组列表

Question

我有一个表熊猫 DF，它看起来像

	奴隶	起始地址0	end_addr0	起始地址1	end_addr1	起始地址2	end_addr2
0	0	10000000	1FFFFFFF	NaN	NaN	NaN	NaN
1	1	2000万	2007FFFF	40000000	40005FFF	NaN	NaN
2	1	2000万	2007FFFF	2010万	201FFFFF	NaN	NaN
3	2	2020万	202FFFFF	20080000	20085FFF	40006000	400FFFFF
4	3	0	0FFFFFFF	NaN	NaN	NaN	NaN
5	4	2030万	203FFFFF	NaN	NaN	NaN	NaN
6	5	20400000	204FFFFF	NaN	NaN	NaN	NaN

对于每个从属编号，我需要将其转换为范围列表（元组）。例如，

Slave1_list = ( (20000000, 2007FFFF), (40000000, 40005FFF), (20100000, 201FFFFF))

从站（行）和地址对（列）的数量可以变化。

谢谢

编辑：

运行以下代码将示例数据加载到数据框中：

import pandas as pd
import io

f = io.StringIO('''Slave|start_addr0|end_addr0|start_addr1|end_addr1|start_addr2|end_addr2
0|10000000|1FFFFFFF|NaN|NaN|NaN|NaN
1|20000000|2007FFFF|40000000|40005FFF|NaN|NaN
1|20000000|2007FFFF|20100000|201FFFFF|NaN|NaN
2|20200000|202FFFFF|20080000|20085FFF|40006000|400FFFFF
3|0|0FFFFFFF|NaN|NaN|NaN|NaN
4|20300000|203FFFFF|NaN|NaN|NaN|NaN
5|20400000|204FFFFF|NaN|NaN|NaN|NaN
''')
df = pd.read_csv(f, sep='|', engine='python', index_col=None)

Answer 1

像下面这样：

import pandas as pd
from collections import defaultdict

data = [{'Slave': 1, 'start_addr0': 12, 'end_addr0': 189, 'start_addr1': 9, 'end_addr1': 17},
        {'Slave': 1, 'start_addr0': 3, 'end_addr0': 6, 'start_addr1': 1, 'end_addr1': 4},
        {'Slave': 3, 'start_addr0': 1, 'end_addr0': 7, 'start_addr1': 2, 'end_addr1': 14}]

df = pd.DataFrame(data)

print(df)
result = defaultdict(list)
rows = df.to_dict(orient='records')
for row in rows:
    slave = row.get('Slave')
    for key, start_value in row.items():
        if key.startswith('start_addr'):
            idx = key[-1]
            end_value = row.get('end_addr' + idx)
            result[slave].append((start_value, end_value))
        else:
            continue

print('result:')
print(result)

输出

   Slave  start_addr0  end_addr0  start_addr1  end_addr1
0      1           12        189            9         17
1      1            3          6            1          4
2      3            1          7            2         14
result:
defaultdict(<class 'list'>, {1: [(12, 189), (9, 17), (3, 6), (1, 4)], 3: [(1, 7), (2, 14)]})