如何在Django管理面板中获取当前记录的用户ID?

Dra*_*tis 3 django django-models django-admin

我有模型消息,它是表单管理器.要填写"user"和"groups"字段,我需要知道当前记录的用户ID,但我不知道如何在保存之前获取它.

class Message(models.Model):
    title = models.CharField(max_length = 100)
    text = models.TextField()
    date = models.DateTimeField(auto_now_add=True)
    user = models.ForeignKey(User, null = True, blank = True)
    main_category = models.ForeignKey(MainCategory)
    sub_category = models.ForeignKey(SubCategory)
    groups = models.ManyToManyField(Group)

class MessageAdminForm(forms.ModelForm):
   def __init__(self, *arg, **kwargs):
       super(MessageAdminForm, self).__init__(*arg, **kwargs)  
       self.initial['main_category'] = MainCategory.objects.get(title = 'News')
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Dan*_*man 7

不要在表格中这样做.覆盖save_model管理子类的方法 - 它可以访问请求.

class MessageAdmin(admin.ModelAdmin):

    def save_model(self, request, obj, form, change):
        obj.user = request.user
        super(MessageAdmin, self).save(request, obj, form, change)
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  • 错误 --- 'super' 对象没有属性 'save' 解决使用 --- super(MessageAdmin, self).save_model(request, obj, form, change) (2认同)