Flask 显示 TypeError: send_from_directory() 缺少 1 个必需的位置参数：'path'

Question

当我在 Azure 上部署 Flask 应用程序时，视图会引发TypeError: send_from_directory() missing 1 required positional argument: 'path'. 当我在本地运行时，这不会发生。

from flask import send_from_directory

@app.route('/download/<path:filename>', methods=['GET', 'POST'])
def download(filename):
    uploads = os.path.join(app.root_path, app.config['UPLOAD_FOLDER'])
    return send_from_directory(directory=uploads, filename=filename)

Answer 1

将最后一行更改为return send_from_directory(uploads, filename).

请参阅有关send_from_directory. 底部的更改日志显示“2.0 版更改：path替换filename参数”。

如果仍要使用命名参数，请更改filename=为path=.send_from_directory(directory=uploads, path=filename)