mar*_*man 7 python ffmpeg numpy
我不确定我所要求的是否可行或有效,但我正在尝试以有序但“按需”的方式从视频加载帧。
基本上我现在所拥有的是通过管道将整个未压缩视频读入缓冲区stdout
,例如:
H, W = 1080, 1920 # video dimensions
video = '/path/to/video.mp4' # path to video
# ffmpeg command
command = [ "ffmpeg",
'-i', video,
'-pix_fmt', 'rgb24',
'-f', 'rawvideo',
'pipe:1' ]
# run ffmpeg and load all frames into numpy array (num_frames, H, W, 3)
pipe = subprocess.run(command, stdout=subprocess.PIPE, bufsize=10**8)
video = np.frombuffer(pipe.stdout, dtype=np.uint8).reshape(-1, H, W, 3)
# or alternatively load individual frames in a loop
nb_img = H*W*3 # H * W * 3 channels * 1-byte/channel
for i in range(0, len(pipe.stdout), nb_img):
img = np.frombuffer(pipe.stdout, dtype=np.uint8, count=nb_img, offset=i).reshape(H, W, 3)
Run Code Online (Sandbox Code Playgroud)
我想知道是否可以在 Python 中执行相同的过程,但无需先将整个视频加载到内存中。在我的脑海里,我正在想象这样的事情:
我知道还有其他库,例如 OpenCV,可以实现相同的行为,但我想知道:
搜索和提取帧是可能的,而且相对简单,无需将整个电影加载到内存中。
当要寻找的请求帧不是关键帧时,存在一些加速损失。
当 FFmpeg 被请求寻找非关键帧时,它会寻找请求帧之前最近的关键帧,并解码从关键帧到请求帧的所有帧。
演示代码示例执行以下操作:
这是代码示例:
import numpy as np
import cv2
import subprocess as sp
import shlex
# Build synthetic 1fps video (with a frame counter):
# Set GOP size to 20 frames (place key frame every 20 frames - for testing).
#########################################################################
W, H = 320, 240 # video dimensions
video_path = 'video.mp4' # path to video
sp.run(shlex.split(f'ffmpeg -y -f lavfi -i testsrc=size={W}x{H}:rate=1 -vcodec libx264 -g 20 -crf 17 -pix_fmt yuv420p -t 60 {video_path}'))
#########################################################################
# ffmpeg command
command = [ 'ffmpeg',
'-ss', '00:00:11', # Seek to 11'th second.
'-i', video_path,
'-pix_fmt', 'bgr24', # brg24 for matching OpenCV
'-f', 'rawvideo',
'-t', '5', # Play 5 seconds long
'pipe:' ]
# Execute FFmpeg as sub-process with stdout as a pipe
process = sp.Popen(command, stdout=sp.PIPE, bufsize=10**8)
# Load individual frames in a loop
nb_img = H*W*3 # H * W * 3 channels * 1-byte/channel
# Read decoded video frames from the PIPE until no more frames to read
while True:
# Read decoded video frame (in raw video format) from stdout process.
buffer = process.stdout.read(W*H*3)
# Break the loop if buffer length is not W*H*3 (when FFmpeg streaming ends).
if len(buffer) != W*H*3:
break
img = np.frombuffer(buffer, np.uint8).reshape(H, W, 3)
cv2.imshow('img', img) # Show the image for testing
cv2.waitKey(1000)
process.stdout.close()
process.wait()
cv2.destroyAllWindows()
Run Code Online (Sandbox Code Playgroud)
注意:当预先知道播放持续时间时,
该参数是相关的。
如果预先未知播放持续时间,您可以在需要时删除并中断循环。-t 5
-t
时间测量:
# 6000 frames:
sp.run(shlex.split(f'ffmpeg -y -f lavfi -i testsrc=size={W}x{H}:rate=1 -vcodec libx264 -g 20 -crf 17 -pix_fmt yuv420p -t 6000 {video_path}'))
# ffmpeg command
command = [ 'ffmpeg',
'-ss', '00:00:11', # Seek to 11'th second.
'-i', video_path,
'-pix_fmt', 'bgr24', # brg24 for matching OpenCV
'-f', 'rawvideo',
'-t', '5000', # Play 5000 seconds long (5000 frames).
'pipe:' ]
# Load all frames into numpy array
################################################################################
t = time.time()
# run ffmpeg and load all frames into numpy array (num_frames, H, W, 3)
process = sp.run(command, stdout=sp.PIPE, bufsize=10**8)
video = np.frombuffer(process.stdout, dtype=np.uint8).reshape(-1, H, W, 3)
elapsed1 = time.time() - t
################################################################################
# Load load individual frames in a loop
################################################################################
t = time.time()
# Execute FFmpeg as sub-process with stdout as a pipe
process = sp.Popen(command, stdout=sp.PIPE, bufsize=10**8)
# Read decoded video frames from the PIPE until no more frames to read
while True:
# Read decoded video frame (in raw video format) from stdout process.
buffer = process.stdout.read(W*H*3)
# Break the loop if buffer length is not W*H*3 (when FFmpeg streaming ends).
if len(buffer) != W*H*3:
break
img = np.frombuffer(buffer, np.uint8).reshape(H, W, 3)
elapsed2 = time.time() - t
process.wait()
################################################################################
print(f'Read all frames at once elapsed time: {elapsed1}')
print(f'Read frame by frame elapsed time: {elapsed2}')
Run Code Online (Sandbox Code Playgroud)
结果:
Read all frames at once elapsed time: 7.371837854385376
Read frame by frame elapsed time: 10.089557886123657
结果表明,逐帧读取存在一定的开销。
归档时间: |
|
查看次数: |
6331 次 |
最近记录: |