如何使用bean中的属性格式化字符串

Question

我想使用一种格式创建一个String,用bean中的属性替换格式的一些标记.是否有一个支持这个的库,或者我将不得不创建自己的实现？

让我举一个例子来证明.说我有一个豆子Person;

public class Person {
  private String id;
  private String name;
  private String age;

  //getters and setters
}

我希望能够指定类似的格式字符串;

"{name} is {age} years old."
"Person id {id} is called {name}."

并使用bean中的值自动填充格式占位符,例如;

String format = "{name} is {age} old."
Person p = new Person(1, "Fred", "32 years");
String formatted = doFormat(format, person); //returns "Fred is 32 years old."

我已经看了一下,MessageFormat但这似乎只允许我传递数字索引,而不是bean属性.

Answer 1

我自己推出，现在测试。欢迎评论。

import java.lang.reflect.Field;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class BeanFormatter<E> {

  private Matcher matcher;
  private static final Pattern pattern = Pattern.compile("\\{(.+?)\\}");

  public BeanFormatter(String formatString) {
    this.matcher = pattern.matcher(formatString);
  }

  public String format(E bean) throws Exception {
    StringBuffer buffer = new StringBuffer();

    try {
      matcher.reset();
      while (matcher.find()) {
        String token = matcher.group(1);
        String value = getProperty(bean, token);
        matcher.appendReplacement(buffer, value);
      }
      matcher.appendTail(buffer);
    } catch (Exception ex) {
      throw new Exception("Error formatting bean " + bean.getClass() + " with format " + matcher.pattern().toString(), ex);
    }
    return buffer.toString();
  }

  private String getProperty(E bean, String token) throws SecurityException, NoSuchFieldException, IllegalArgumentException, IllegalAccessException {
    Field field = bean.getClass().getDeclaredField(token);
    field.setAccessible(true);
    return String.valueOf(field.get(bean));
  }

  public static void main(String[] args) throws Exception {
    String format = "{name} is {age} old.";
    Person p = new Person("Fred", "32 years", 1);

    BeanFormatter<Person> bf = new BeanFormatter<Person>(format);
    String s = bf.format(p);
    System.out.println(s);
  }

}