4 python matplotlib pandas pie-chart
我在使用 Python 的 Matplotlib 绘制嵌套饼图时遇到问题。我编写了一些代码来处理这个过程,但我有一个与设计和标签相关的问题
我想画一种这种嵌套饼图。(从最上层嵌套到最内层是SEX,ALIGN并覆盖它们的计数)
这是我的数据框,如下所示。
ALIGN SEX count
2 Bad Characters Male Characters 1542
5 Good Characters Male Characters 1419
3 Good Characters Female Characters 714
0 Bad Characters Female Characters 419
8 Neutral Characters Male Characters 254
6 Neutral Characters Female Characters 138
1 Bad Characters Genderless Characters 9
4 Good Characters Genderless Characters 4
7 Neutral Characters Genderless Characters 3
9 Reformed Criminals Male Characters 2
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这是我与显示嵌套饼图相关的代码片段,如下所示。
fig, ax = plt.subplots(figsize=(24,12))
size = 0.3
ax.pie(dc_df_ALIGN_SEX.groupby('SEX')['count'].sum(), radius=1,
labels=dc_df_ALIGN_SEX['SEX'].drop_duplicates(),
autopct='%1.1f%%',
wedgeprops=dict(width=size, edgecolor='w'))
ax.pie(dc_df_ALIGN_SEX['count'], radius=1-size, labels = dc_df_ALIGN_SEX["ALIGN"],
wedgeprops=dict(width=size, edgecolor='w'))
ax.set(aspect="equal", title='Pie plot with `ax.pie`')
plt.show()
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如何设计 4 行和 4 列,并将每一个放入每个插槽中并在图例区域中显示标签?
由于问题已更改,我将发布新答案。
首先,我稍微简化了您的 DataFrame:
import pandas as pd
df = pd.DataFrame([['Bad', 'Male', 1542],
['Good', 'Male', 1419],
['Good', 'Female', 714],
['Bad', 'Female', 419],
['Neutral', 'Male', 254],
['Neutral', 'Female', 138],
['Bad', 'Genderless', 9],
['Good', 'Genderless', 4],
['Neutral', 'Genderless', 3],
['Reformed', 'Male', 2]])
df.columns = ['ALIGN', 'SEX', 'n']
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对于外环中的数字,我们可以使用简单的groupby,就像您所做的那样:
outer = df.groupby('SEX').sum()
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但对于内环中的数字,我们需要按两个分类变量进行分组,这会产生 MultiIndex:
inner = df.groupby(['SEX', 'ALIGN']).sum()
inner
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n
SEX ALIGN
Female Bad 419
Good 714
Neutral 138
Genderless Bad 9
Good 4
Neutral 3
Male Bad 1542
Good 1419
Neutral 254
Reformed 2
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我们可以使用它的方法从 MultiIndex 中提取适当的标签get_level_values():
n
SEX ALIGN
Female Bad 419
Good 714
Neutral 138
Genderless Bad 9
Good 4
Neutral 3
Male Bad 1542
Good 1419
Neutral 254
Reformed 2
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现在您可以将上述值转换为一维数组并将它们插入到您的绘图调用中:
inner_labels = inner.index.get_level_values(1)
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