paz*_*zof 2 php laravel eloquent eloquent-relationship
Laravel/Eloquent 新手在这里。我正在实现一个简单的棋盘游戏。每场比赛有 4 名玩家。表结构由 Players 表和 Games 表组成:
SELECT * FROM players;
id | name |
---------------------
1 | John |
2 | Mary |
3 | Linda |
4 | Alex |
5 | Chris |
6 | Ron |
7 | Dave |
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SELECT * FROM games;
id | player1_id | player2_id | player3_id player4_id
---------------------------------------------------------------------
1 | 1 | 2 | 3 | 4
2 | 3 | 5 | 6 | 7
3 | 2 | 3 | 5 | 6
4 | 2 | 4 | 5 | 7
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目标:我希望能够获取玩家参与过的所有游戏。
为此,我尝试games()在 Player 模型中编写一个函数。对于 ID 为 2 的玩家,应返回游戏 1、3、4;对于 ID 为 3 的玩家,应返回游戏 1、2、3,依此类推。
使用原始 SQL 我会做这样的事情:
SELECT * FROM games WHERE
(player1_id = 2 OR player2_id = 2 OR player3_id = 2 OR player4_id = 2)
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但对于 Eloquent,我很难弄清楚必须如何建立这种关系才能实现这一目标。
同样,我也希望能够使用模型players()中的函数执行相反的操作 - 返回游戏的所有玩家Game。
型号:
// Models/Player.php
//...
class Player extends Model
{
public function games(){
//?
}
}
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// Models/Game.php
//...
class Game extends Model
{
public function players(){
//?
}
}
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在不更改数据库结构的情况下,您可能会滥用声明hasMany来获取所有 4 个玩家。
class Game extends Model
{
public function players()
{
return $this->hasMany(Player::class, 'id', 'player1_id')
->orWhere('id', $this->player2_id)
->orWhere('id', $this->player3_id)
->orWhere('id', $this->player4_id);
}
}
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class Player extends Model
{
public function games()
{
return $this->hasMany(Game::class, 'player1_id', 'id')
->orWhere('player2_id', $this->id)
->orWhere('player3_id', $this->id)
->orWhere('player4_id', $this->id);
}
}
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然而这并不理想。
您应该有第三个表来正确映射这种多对多关系。
table 1 - players: id (pk), name
table 2 - games: id (pk)
table 3 - game_player: id (pk), game_id (fk), player_id (fk), unique([game_id, player_id])
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table 1 - players: id (pk), name
table 2 - games: id (pk)
table 3 - game_player: id (pk), game_id (fk), player_id (fk), unique([game_id, player_id])
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class Game extends Model
{
public function players()
{
return $this->belongsToMany(Player::class, 'game_player');
}
}
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