如何在Android应用程序上放置超链接到网站？

Question

我想在我正在开发的Android应用程序上放置一个超链接.

我试过这个:

main.xml中

<TextView 
android:layout_width="fill_parent" 
android:layout_height="fill_parent" 
android:text="@string/hyperlink"
android:id="@+id/hyperlink" 
android:autoLink="web"
>
</TextView>

strings.xml

<?xml version="1.0" encoding="utf-8"?>
<resources>
<string name="app_name">WebLink</string>
<string name="hyperlink">http://google.com</string>
</resources>

但问题是,链接看起来像这样:http://google.com并且我不想显示实际的网址.

1)如何通过"点击此处访问Google"等文本替换链接,文本是否与网站网址链接？

2)如何放置电子邮件地址(同样的问题,如何用"Click Here to Email"等文本替换它,文本应该与email@domain.com链接)

---

我也试过这个教程:http://coderzheaven.com/2011/05/10/textview-with-link-in-android/

但我收到以下错误消息:

Description Resource    Path    Location    Type
http cannot be resolved to a variable   MyLink.java /MyLink/src/com/MyLink  line 21 Java Problem
Syntax error on token "" <br /> <a href="", ? expected after this token MyLink.java /MyLink/src/com/MyLink  line 21 Java Problem
Type mismatch: cannot convert from String to boolean    MyLink.java /MyLink/src/com/MyLink  line 20 Java Problem

Answer 1

使用默认的Linkify类.

这是一个示例和教程中的代码:

这是我的示例代码,我认为这将解决您的问题:

    public class StackOverflowActivity extends Activity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        // 1) How to replace link by text like "Click Here to visit Google" and
        // the text is linked with the website url ?
        TextView link = (TextView) findViewById(R.id.textView1);
        String linkText = "Visit the <a href='http://stackoverflow.com'>StackOverflow</a> web page.";
        link.setText(Html.fromHtml(linkText));
        link.setMovementMethod(LinkMovementMethod.getInstance());
        // 2) How to place email address
        TextView email = (TextView) findViewById(R.id.textView2);
        String emailText = "Send email: <a href=\"mailto:person@stackoverflow.com\">Click Me!</a>";
        email.setText(Html.fromHtml(emailText));
        email.setMovementMethod(LinkMovementMethod.getInstance());
    }
}