如何实现抽象基类的构造函数？

Question

我正在尝试编写一个基本抽象类，它具有一些将使用构造函数初始化的属性。到目前为止我有这个：

from abc import ABC, abstractmethod

class A(ABC):
    def __init__(self, n, *params):
        self.n = n
        self.initialize_params(*params) #I want to do this in all subsclasses of A
    def initialize_params(self, *params)
       pass
    @abstractmethod
    def do(self):
        pass

class B(A):
    def __init__(self, m, n, *super_params):
        self.m = m
        super(A, self).__init__(n, *super_params)
    def do(self):
        print("this is B")

但这会TypeError因为__init__B 中 A 的实例化而抛出。正确的方法是什么？

Answer 1

您似乎有几个错误：

from abc import ABC, abstractmethod

class A(ABC):
    def __init__(self, n, *params):
        self.n = n
        self.initialize_params(*params) #I want to do this in all subsclasses of A
    def initialize_params(self, *params):
        pass
    @abstractmethod
    def do(self):
        pass

class B(A):
    def __init__(self, m, n, *super_params):
        self.m = m
        super().__init__(n, *super_params)  # correct way to use super() to call init
    def do(self):
        print("this is B")


b = B(1,2)
b.do()

请注意，您错过了self.前面的内容initialize_params()，而且您似乎没有super()正确使用。