假设我想直接从 a 读取对象水果Json file并将其存储到Fruit.class. 我该怎么做?
{
"fruits": [
{ "name":"Apple", "price":"0.8"}
],
"vegetables": [
{ "name":"Carrot", "price":"0.4"}
]
}
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我的模型 class
public class Fruit {
private String name;
private double price;
public String getName() { return name; }
public void setName(String name) { this.name = name; }
public double getPrice() { return price; }
public void setPrice(double price) { this.price= price; }
}
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我试过的:
String file = "src/main/resources/basket.json";
String json = new String(Files.readAllBytes(Paths.get(file)));
objectMapper.readValue(json, Fruit.class);
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您的 json 必须与您尝试转换的内容相匹配。在你的情况下,你需要
public class FruitWrapper {
private List<Fruits> fruits;
private List<Fruits> vegetables;
getters, setters...
}
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那么这对你有用
FruitWrapper fruitWrapper = objectMapper.readValue(json, FruitWrapper.class);
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