Nic*_*uer 8 java ssl proxy cxf
所以这是交易.我有一个Web服务WSDL,我需要在公司网络外部进行SOAP调用.Web服务是HTTPS SOAP,需要客户端证书.我用Java生成了客户端代码wsdl2java,事情看起来很顺利.
我现在不能做的是通过CXF从Web服务收到回复.SSL握手似乎只是花花公子甚至达到了CXF尝试进行HTTP POST的程度,但是超时等待响应(如下所示):
Allow unsafe renegotiation: false
Allow legacy hello messages: true
Is initial handshake: false
Is secure renegotiation: false
*** HelloRequest (empty)
main, SEND TLSv1 ALERT: warning, description = no_renegotiation
Padded plaintext before ENCRYPTION: len = 24
0000: 01 64 01 FD 5B 38 03 A6 70 41 57 58 6D 75 60 F7 .d..[8..pAWXmu`.
0010: 93 1F 02 F3 C4 46 01 01 .....F..
main, WRITE: TLSv1 Alert, length = 24
[Raw write]: length = 29
0000: 15 03 01 00 18 0C 9B DF 1B 60 AB 12 EE C7 CF C9 .........`......
0010: 62 97 A5 5D 5F 14 48 E1 9F AD 8A 08 05 b..]_.H......
main, handling exception: java.net.SocketTimeoutException: Read timed out
main, called close()
main, called closeInternal(true)
main, SEND TLSv1 ALERT: warning, description = close_notify
Padded plaintext before ENCRYPTION: len = 24
0000: 01 00 BD 99 7A 7C 72 1F BB 11 2D AB 3F 53 C9 CD ....z.r...-.?S..
... continuing on
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现在,如果我使用curl或者类似的东西,我可以在不到一秒的时间内获得响应,所以我知道Web服务没有错.下面是创建服务端口所需的全部代码,包括使用TLS和HTTP代理进行设置.我有一个非常简单的JUnit测试来创建和运行它:
public static MYPORT setupTLS(MYPORT port) throws IOException,
GeneralSecurityException {
HTTPConduit httpConduit = (HTTPConduit) ClientProxy.getClient(port)
.getConduit();
String keyPassword = "password";
KeyStore keyStore = KeyStore.getInstance("pkcs12");
URL pkcs12_file = MECTPortFactory.class.getResource(System
.getProperty("pkcs12.keyFile"));
InputStream keyFile = pkcs12_file.openStream();
keyStore.load(keyFile, keyPassword.toCharArray());
KeyManager[] myKeyManagers = getKeyManagers(keyStore, keyPassword);
TLSClientParameters tlsCP = new TLSClientParameters();
tlsCP.setKeyManagers(myKeyManagers);
tlsCP.setDisableCNCheck(true);
FiltersType cipher_suite_filter = new FiltersType();
cipher_suite_filter.getInclude().add("SSL_RSA_WITH_3DES_EDE_CBC_SHA");
cipher_suite_filter.getExclude().add(".*_DH_anon_.*");
tlsCP.setCipherSuitesFilter(cipher_suite_filter);
httpConduit.setTlsClientParameters(tlsCP);
httpConduit.setClient(getHttpClient());
return port;
}
private static HTTPClientPolicy getHttpClient() {
HTTPClientPolicy client_policy = new HTTPClientPolicy();
client_policy.setProxyServer("PROXY_SERVER_ADDRESS");
client_policy.setProxyServerPort(8080);
client_policy.setAutoRedirect(true);
client_policy.setConnection(ConnectionType.KEEP_ALIVE);
client_policy.setAllowChunking(true);
client_policy.setReceiveTimeout(10000);
return client_policy;
}
private static KeyManager[] getKeyManagers(KeyStore keyStore,
String keyPassword) throws GeneralSecurityException, IOException {
String alg = KeyManagerFactory.getDefaultAlgorithm();
char[] keyPass = keyPassword != null ? keyPassword.toCharArray() : null;
KeyManagerFactory fac = KeyManagerFactory.getInstance(alg);
fac.init(keyStore, keyPass);
return fac.getKeyManagers();
}
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我已经摆弄了一些客户端设置,例如更改是否AutoRedirect,AllowChunking等,没有任何差异,所以我不认为这会导致错误.
我没有得到网络服务的回复. 如何排除故障并修复导致CXF超时而不是接收响应的原因?
我的天啊!我想到了.
所以我穿过了互联网,发现了这个小宝石:
它引用了Oracle/Sun的一个非常重要的注释:
从对等方接收重新协商请求的应用程序将根据所处的连接类型进行响应:
TLSv1:类型为"no_renegotiation(100)"的警告警报消息将发送给对等方,连接将保持打开状态.
然后,进一步下来:
重新谈判可以重新启用那些通过设置新的系统属性需要它应用
sun.security.ssl.allowUnsafeRenegotiation到true之前的JSSE库被初始化.有几种方法可以设置此属性:
命令行:
% java -Dsun.security.ssl.allowUnsafeRenegotiation=true MainJava控制面板(Java插件/ Java Web Start) - 运行时环境.
在申请中:
java.lang.System.setProperty("sun.security.ssl.allowUnsafeRenegotiation", true);请注意,除非客户端和服务器都启用了重新协商,否则不会发生TLS/SSL重新协商.
那么多空呢? System.setProperty("sun.security.ssl.allowUnsafeRenegotiation", "true");
和事情.只是.工作.
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