use*_*579 2 perl hash perl-data-structures
嗨,我有一个哈希哈希,包含班级名称,注册学生人数和学生姓名.
如何打印此哈希而不重复第二级键.
示例:我填写的哈希数据是Science Class,3名学生就读于George,Lisa,Mathias和Math Class,4名学生注册了Peter,George,Anna,Martin.
my %register=();
$register{$className}->{$count_students}=$student_name; # Fill the hash.
foreach my $key ( keys %register ){
print "$key: ";
foreach my $class ( keys %{ $register{$key} } ){
print "$class=$register{$key}->{$class}\n";
}
}
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我得到的结果如下:
Science_class:2 = Lisa
1 = George
3 = Mathias
Math_class:2 = Anna
1 = Martin
3 = Peter
4 = George
但我希望我的结果如下:
Science_class:3 - > Lisa,George,Mathias
Math_class:4 - > Anna,Martin,Peter,George
如何更正我的脚本?帮帮我.
您可以使用keys标量上下文中的函数获取第二级中的条目数,并且您可以使用该函数获得第二级中的values值.
#!/usr/bin/perl
use strict;
use warnings;
my %register = (
Science_class => {
1 => "George",
2 => "Lisa",
3 => "Mathias",
},
Math_class => {
1 => "Martin",
2 => "Anna",
3 => "Peter",
4 => "George",
}
);
for my $class (keys %register) {
print "$class: ", scalar keys %{$register{$class}},
" ", join(", ", values %{$register{$class}}), "\n";
}
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但是,考虑到数据的结构,arrayrefs的散列更有意义:
#!/usr/bin/perl
use strict;
use warnings;
my %register = (
Science_class => [
"George",
"Lisa",
"Mathias",
],
Math_class => [
"Martin",
"Anna",
"Peter",
"George",
]
);
for my $class (keys %register) {
print "$class: ", scalar @{$register{$class}},
" ", join(", ", @{$register{$class}}), "\n";
}
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您可能会发现阅读perldoc perldsc有助于理解如何在Perl 5中创建和操作数据结构.