在Webview中打开链接而不是默认浏览器

Question

我有这段代码:

    TextView noteView = (TextView) view.findViewById(R.id.content);
    noteView.setMovementMethod(LinkMovementMethod.getInstance());
    noteView.setText(Html.fromHtml(noteView.getText().toString()));

我需要在webview中打开链接,而不是在浏览器中打开...这可能吗？我能怎么做？？

提前致谢..

Answer 1

另外,你可以这样做.

    package com.TextHtml;

    import android.app.Activity;  
    import android.content.Context;  
    import android.os.Bundle;  
    import android.text.Html;  
    import android.text.Spannable;  
    import android.text.SpannableStringBuilder;  
    import android.text.method.LinkMovementMethod;  
    import android.text.style.ClickableSpan;  
    import android.text.style.URLSpan;  
    import android.view.View;  
    import android.widget.TextView;  
    import android.widget.Toast;  
    public class TextHtml extends Activity {

        private TextView  tv;  
        static Context ctx=null;  
        @Override  
        public void onCreate(Bundle savedInstanceState) {  
            super.onCreate(savedInstanceState);  
            setContentView(R.layout.main);  
            ctx=this;  
            tv = (TextView) findViewById(R.id.tv);   
            String htmlLinkText = "<a href="/" mce_href="/""http://www.google.com/"><u>hello google </u></a>";     
            tv.setText(Html.fromHtml(htmlLinkText));  
            tv.setMovementMethod(LinkMovementMethod.getInstance());     
            CharSequence text = tv.getText();     
            if(text instanceof Spannable){     
                int end = text.length();     
                Spannable sp = (Spannable)tv.getText();     
                URLSpan[] urls=sp.getSpans(0, end, URLSpan.class);      
                SpannableStringBuilder style=new SpannableStringBuilder(text);     
                style.clearSpans();//should clear old spans     
                for(URLSpan url : urls){     
                    CustomerTextClick click = new CustomerTextClick(url.getURL());     
                    style.setSpan(click,sp.getSpanStart(url),sp.getSpanEnd(url),Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);     
                }     
                tv.setText(style);     
            }  
        }  

        private static class CustomerTextClick extends ClickableSpan{     

            private String mUrl;     
            MyURLSpan(String url) {     
                mUrl =url;     
            }     
            @Override  
            public void onClick(View widget) {  
                // TODO Auto-generated method stub  
                Toast.makeText(ctx, "hello google!",Toast.LENGTH_LONG).show();  
            }     
        }  
    } 

Answer 2

是的,您可以这样做,使用WebView这是非常简单的任务,您需要声明一个WebViewClient对象并覆盖该public boolean shouldOverrideUrlLoading (WebView view, String url)方法,您可以在那里过滤网址或提供一些自定义功能.

在您的情况下,要保持WebView,您需要在该方法上返回false.

看看这个教程.

问候

编辑:

看来你的问题是如何在TextView的url上处理click事件.正如在此问题上建议的那样,您可以ACTION_VIEW在包含Activity的WebView上过滤意图.如果您需要有关intent-filters的更多指导,请查看此信息.