Python异常中的行号

Question

如何获取Python中异常的行号？


以下代码的输出

try:
    print("a" + 1)
except Exception as error_message:
    print("There was an error: " + str(error_message))

是

There was an error: can only concatenate str (not "int") to str

但不仅仅是打印

"There was an error: " + str(error_message)

如何像这个例子一样打印行号

try:
    print("a" + 1)
except Exception as error_message and linenumber as linenumber:
    print("There was an error: " + str(error_message) + ". The line where the code failed was " + str(linenumber))

预期输出为

There was an error: can only concatenate str (not "int") to str. The line where the code failed was 2

这对我调试项目时非常有用

Answer 1

import traceback

try:
    print("a" + 1)
except Exception as e:
    print("There was an error: " + e.args[0] + ". The line where the code failed was " + str(traceback.extract_stack()[-1][1]))