C#如何将大型HEX字符串转换为二进制

Question

我有一个包含14个字符的字符串.这是7字节的十六进制represantation.我想将其转换为二进制.我试过使用Convert.ToString(Convert.ToInt32(hexstring, 16), 2);For small strings这个有效,但对于14个字符,它不起作用,因为结果太大了.我该怎么办呢？请记住,转换的输出应该是一个二进制字符串,其长度为56个字符(我们必须保留前导零).(例如,(byte)0x01的转换应该产生"00000001"而不是"1")

Answer 1

您可以将每个十六进制数字转换为四个二进制数字:

string binarystring = String.Join(String.Empty,
  hexstring.Select(
    c => Convert.ToString(Convert.ToInt32(c.ToString(), 16), 2).PadLeft(4, '0')
  )
);

你需要一个using System.Linq;文件的顶部才能工作.

Answer 2

Convert.ToString(Convert.ToInt64(hexstring, 16), 2);

也许？要么

Convert.ToString(Convert.ToInt64(hexstring, 16), 2).PadLeft(56, '0');

Answer 3

为什么不采用简单的方法并定义自己的映射？

private static readonly Dictionary<char, string> hexCharacterToBinary = new Dictionary<char, string> {
    { '0', "0000" },
    { '1', "0001" },
    { '2', "0010" },
    { '3', "0011" },
    { '4', "0100" },
    { '5', "0101" },
    { '6', "0110" },
    { '7', "0111" },
    { '8', "1000" },
    { '9', "1001" },
    { 'a', "1010" },
    { 'b', "1011" },
    { 'c', "1100" },
    { 'd', "1101" },
    { 'e', "1110" },
    { 'f', "1111" }
};

public string HexStringToBinary(string hex) {
    StringBuilder result = new StringBuilder();
    foreach (char c in hex) {
        // This will crash for non-hex characters. You might want to handle that differently.
        result.Append(hexCharacterToBinary[char.ToLower(c)]);
    }
    return result.ToString();
}

请注意,这将保持前导零.因此"aa"将被转换为"10101010"while "00000aa"将被转换为"0000000000000000000010101010".

Answer 4

您可以使用此代码从十六进制字符串获取字节数组

 public static byte[] StringToByteArray(String hex)
    {
        int NumberChars = hex.Length;
        byte[] bytes = new byte[NumberChars / 2];
        for (int i = 0; i < NumberChars; i += 2)
            bytes[i / 2] = Convert.ToByte(hex.Substring(i, 2), 16);
        return bytes;
    }