查询不像其他人一样工作

Question

我为我的生活无法弄清楚为什么当我试图回应它时,这不是输出0.它适用于上一个查询,但不适用于最后一个查询.

// This one works and if there are no movies above 0 then it outpus 0 fine
$tag_movies_result = mysql_query("SELECT * FROM tags WHERE tagname='$n' AND movie > 0");
$total_times_used_movies = mysql_num_rows($tag_movies_result);

// Where as this query returns an error 
$tag_shows_result = mysql_query("SELECT * FROM tags WHERE tagname='$n' AND show > 0"); <-- `show`
$total_times_used_shows = mysql_num_rows($tag_shows_result); <-- Line 12

// the error
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/a5410474/public_html/tags/tag.php on line 12

这就是我用它来称呼它

<li><a href="#shows" rel="shows">Shows (<?php echo $total_times_used_shows; ?>)</a></li>

演示:http://mydb.host56.com/tags.php？n = the

列名称SHOWS需要包含在`中.主题已关闭.

Answer 1

SHOW是显示的关键字wrap tilde(`),如下所示:

`show` 

参考